to avoid a large shallow reef a ship set a course from point a and traveled 24 miles east to point b . the ship them turn and tr
aveled 33 miles south to point c. if the ship could have traveled in a straight lime from point a to point c about how many miles could it have saved
1 answer:
First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi
Next, we are going to use the Pythagorean theorem to find the distance from

to

:


d^2=1665


mi
Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi
We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved
16.2 miles.</span>
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<span>5t=3b+660....and ... 2t+5b=450
from the first we can see that t=(3b+660)/5 and using this value in the second...
(6b+1320)/5+5b=450 making all have common denominator..
6b+1320+25b=2250
31b=930
b=30...and since 2t+5b=450
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Answer:
4,337 goes on top & 8 on the bottom
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8 & the answer is 542.12
Answer:
13
Step-by-step explanation:
substitute all the numbers in
6+3/6+3/6+6=13
There are 25 in the class
Answer: w = -3u/2 + 2
Step-by-step explanation:
-12u + 13 = 8w - 3
-12u + 13 + 3 = 8w -3 + 3
-12u + 16 = 8w
w = -3u/2 + 2