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Serggg [28]
3 years ago
14

to avoid a large shallow reef a ship set a course from point a and traveled 24 miles east to point b . the ship them turn and tr

aveled 33 miles south to point c. if the ship could have traveled in a straight lime from point a to point c about how many miles could it have saved

Mathematics
1 answer:
Sever21 [200]3 years ago
7 0
First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi

Next, we are going to use the Pythagorean theorem to find the distance from a to c:
d^2=24^2+33^2
d^2=576+1089
d^2=1665
d= \sqrt{1665}
d=40.8 mi

Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi

We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>

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Zen spent $255 on a bag and a belt. She wanted to buy another
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Answer:

A)$ 45

B) $105

Step-by-step explanation:

Bag and a belt cost $255

Let bag = x

Let belt = y

X+y= 255 equation 1

Let total money be z first

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X-30 = z-255

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Equating the left side of the equation

X+30 = y+15

X-y= 45 equation 2

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If x= 150

150-y= 45

150-45= y

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Bag = $150

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Bag Is 150-105 more than the belt

150-105= $45

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3 years ago
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Answer:

- 40

Step-by-step explanation:

5(a - 4b) \\  = 5 \bigg(- 7 - 4 \times \frac{1}{4} \bigg ) \\ = 5 \bigg(- 7 - 1 \bigg ) \\  = 5 \times ( - 8) \\  =  - 40

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