Answer:
<h2>11</h2>
Step-by-step explanation:
Given h(t) = t²+t+ 12 and k(t) = √t-1, we are to find k(k.h)(10)
k{h(t)} = k{ t²+t+ 12}
Since k(t)= √t-1, we will replace the variable t in the function with t²+t+ 12
k(h(t)) = √{(t²+t+ 12)-1}
k(h(t)) = √t²+t+12-1
k(h(t)) = √t²+t+11
Substituting t = 10 into the resulting function;
k(h(10)) = √(10)²+(10)+11
k(h(10)) = √100+10+11
k(h(10)) = √121
<em>k(h(10))= 11</em>
<em></em>
<em>hence the value of (k compose h) (10) is 11</em>
Answer:
Step-by-step explanation it’s d
The answer is 11 because you add all the numbers then divide by the number of terms which would be 44/4=11
Its <span>isosceles triangle</span>
Answer:
∠ A ≈ 24.1°
Step-by-step explanation:
Using the law of sines , then
= ( cross- multiply )
21 × sinA = 9 × sin72° ( divide both sides by 21 )
sinA = , then
∠ A = ( ) ≈ 24.1° ( to the nearest tenth )