The number that should go in the box is 6.
3.60
- 0.65
---------------
2. 9 5
Answer:
$4,499.46
Step-by-step explanation:
We can use the compound interest formula for this problem:
![A=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
P = initial balance
r = interest rate (decimal)
n = number of times compounded annually
t = time
First, lets change 4% into a decimal:
4% ->
-> 0.04
Now lets plug the values into the equation as shown below:
![A=4,000(1+\frac{0.04}{1})^{1(3)}](https://tex.z-dn.net/?f=A%3D4%2C000%281%2B%5Cfrac%7B0.04%7D%7B1%7D%29%5E%7B1%283%29%7D)
![A=4,499.46](https://tex.z-dn.net/?f=A%3D4%2C499.46)
Don will have $4,499.46 at the end of the three years.
Answer:
1/10
Step-by-step explanation:
93÷93 930÷93
=1/10
Answer:
Probability that one of them is mathematics and other two are either physics or history books = 0.51
Step-by-step explanation:
Given - A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.
To find - What is the probability one of them is mathematics and other two are either physics or history books ?
Solution -
Given that,
A student needs to select 3 books from 3 different mathematics, 3 different physics and 1 history books.
So,
Total number of books = 3 + 3 + 1 = 7
The student has to select 3 books
So, Total number of ways =
= 35
So,
Probability that one of them is mathematics and other two are either physics or history books is -
= ![\frac{^{3} C_{1}. ^{4} C_{2} }{^{7} C_{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5E%7B3%7D%20C_%7B1%7D.%20%5E%7B4%7D%20C_%7B2%7D%20%20%7D%7B%5E%7B7%7D%20C_%7B3%7D%7D)
= ![\frac{(3)(6)}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B%283%29%286%29%7D%7B35%7D)
= ![\frac{18}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B35%7D)
= 0.51
⇒Probability that one of them is mathematics and other two are either physics or history books = 0.51