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svet-max [94.6K]
2 years ago
12

Write the equations of the horizontal and vertical lines going through the point (-2,-5)​

Mathematics
1 answer:
WARRIOR [948]2 years ago
8 0

Answer:

the horizon is to inform that we are still here in a few days I have not what you mean about that language arts center for a while but not sure just asking for I don't have a

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Nate walked 72 city blocks in 48 minutes. At this rate, how many city blocks can he walk in 90 minutes?
stiv31 [10]

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135 city blocks is the correct answer

Step-by-step explanation:

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Determine the lateral and total surface
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The answer to your question would be 16
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Brendan bought an iced tea that cost $4.06 plus 7% sales tax. If Brendan left an 18% tip on the $4.06, how much in total did he
ahrayia [7]

Answer:

Step-by-step explanation:

18% tip in $=18/100 * $4.06

$0.7308

7% sales tax in $= 7/100 * $4.06

$0.2842

Total amount he paid= $0.7308+$0.2842+$4.06

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2 years ago
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I don't understand what the question is asking?
lana66690 [7]
OK for this question you need to find out how many more post are needed. If you look at the diagram it shows that one side is 50 feet.  Now there are two sides that will need post, because the barn side need no more.  Now if there are two side both 50 feet, and you need a post every ten feet. How many posts are needed? 

5 0
3 years ago
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°
Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = c^{2} = a^{2} + b^{2}

a = 7 and b = 11

a^{2} = 49

b^{2} = 121

Plugging in the values, we will get:

c^{2} = 49 + 121

c^{2} = 170

c = \sqrt{170}

To calculate the unknown angle B, we can use law of sine.

Law of sine = \frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

So,

\frac{c}{sinC} = \frac{b}{sinB}

\frac{\sqrt{170} }{sin90} =  \frac{11}{sinB}

Sin90 = 1

sinB = \frac{11}{\sqrt{170} }

B = sin^{-1} (\frac{11}{\sqrt{170} })

B = 57.5°

8 0
3 years ago
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