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2 years ago

8

How to solve the problem

1 answer:

WINSTONCH [101]2 years ago

7 0

As tgose lines are parallel then,

a = 140° ( by alternate interior angles)

then,
tha angle just below "a" on the other paralle line would also be 140° by corresponding angles,

using exterior angle property of triangle

66° + b = 140°

b = 140° -66
= 74°

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suter [353]

Answer:

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Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

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Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

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Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

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Step-by-step explanation:

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Read 2 more answers

6x^2 + 66x + 60 factor completely

kiruha [24]

Hi! Let me help you!

Remember, factoring looks like so:
ab+ac=a(b+c)
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In this case, 6 is the GCF, so we factor it out:
6x²+66x+60
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<u>Answer:</u>

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Hope you find it helpful.

$\rm{Stargazing{\bold{WithJoy}$

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You should
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