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3 years ago

HELP ME PLEASEEEEEEEEEEEE

Mathematics

2 answers:

laila [671]3 years ago

8 0

Answer:

1080 in^2

Step-by-step explanation:

evablogger [386]3 years ago

8 0

Answer:

180 in^2

Step-by-step explanation:

A 12" wide by 30" flag has the area A = (1/2)(base)(height) square inches, or 180 square inches.

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Ronch [10]

Answer:

Step-by-step explanation:

<h3>Question:-</h3>

To find the Binomial theorem form of $\bold{(4t-3)^{5}}$

As in Binomial theorem :-

${(x - y)}^{5} = {x}^{5} - 5 {x}^{4} y + 10 {x}^{3} {y}^{2} - 10 {x}^{2} {y}^{3} + 5x {y}^{4} - {y}^{5}$

<h3>Solution :-</h3>

$= {(4t - 3)}^{5}$

Hence, on using the Binomial theorem,

$= {(4t)}^{5} - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3} {(3)}^{2} - 10 {(4t)}^{2} {(3)}^{3} + 5(4t) {(3)}^{4} - {(3)}^{5}$

On formatting

$= {1024t}^{5} - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2} )(27) + 5(4t) (81) - 243$

On further formatting.

$= {1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

Hence, the required answer is :-

${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

6 0

2 years ago

If f ( 4 ) = − 2 , write an ordered pair that must be on the graph of y = f ( x + 4 ) + 1

AlekseyPX

We have been given that

$y = f ( x + 4 ) + 1\\
\\
f(4)=-2$

Now, we need to find an ordered pair that must be on the graph of

$y = f ( x + 4 ) + 1$

On substituting x=0 in the above equation, we get

$y = f ( 0 + 4 ) + 1\\
\\
y=f(4)+1\\
\\
\text{On substituting the value of f(4)= -2, we get}\\
\\
y=-2+1\\
y=-1$

Therefore, the required ordered pair is given by (0,-1)

4 0

3 years ago

What is the product of z1 and z2 if

MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

z1z2 = 154sqrt(2) + (i)154sqrt(2)

sqrt: square root

8 0

3 years ago

(05.05)

Bas_tet [7]

Answer:

Step-by-step explanation:

The initial value is when x=0

When x=0, y =5

The initial value is 5

3 0

2 years ago

Hi can someone help me with the last two sets of shapes? Thank you so much! -Jenn

SOVA2 [1]

You are correct there's at least one obtuse angle

8 0

3 years ago