$\frac{4}{y^{2}-9 } + \frac{5}{y+3} = \frac{4}{(y-3)(y+3) } + \frac{5}{y+3}= \frac{4}{(y-3)(y+3) } + \frac{5(y-3)}{(y-3)(y+3)}=
\\ \\=\frac{4}{(y-3)(y+3) } + \frac{5y-15}{(y-3)(y+3)}= \frac{5y-11}{(y-3)(y+3)}=\frac{5y-11}{y^{2}-9}
$

8 0

3 years ago

Please assist with this question!!!!!!!!!! No links or your account will be banned

andriy [413]

Answer:

8/15

Step-by-step explanation:

4 0

2 years ago

Melissa has enough paint to cover an area of 250 square feet.she want to paint two walls.the rectangular wall is 9 feet high and

liraira [26]

Answer:

No she doesn't have enough paint.

Step-by-step explanation:

You have to find the area of both walls then subtract both areas by 250. It would give you a negative number, meaning there is not enough paint.

5 0

3 years ago

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