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Juliette [100K]
3 years ago
13

What is 30xy -28xy -xy in simple form

Mathematics
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

1xy

Step-by-step explanation:

30xy-28xy=2xy-xy=xy or 1xy

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What is a possible value for the missing term of the geometric sequence 35,_,875,...
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The value for the missing term is -175.
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Find the distance between 2 and -2<br><br> A. -6<br> B -4 <br> C. 0<br> D. 4
tangare [24]

Answer:

b) -4

Step-by-step explanation:

Well your at 2 and going to -2 so on a number line you be going back or left.

Going two left gets you to zero and going two more get you -2. So in total you went back four and that be represented as -4.

5 0
3 years ago
What is percent change from $18 to 28$? Round to nearest tenth place​
zavuch27 [327]

Answer:

35.2%

Step-by-step explanation:

3 0
4 years ago
Help me solve this pleasee *ASAP this is currently a homework assignment thats due in 45 mintues**
klio [65]

Answer:

The value of y is 36, and the value of z is 54.

Step-by-step explanation:

y has to be a number that can sit at 2y and then add itself to itself and become 3y.

40 is too high, and 35 is too low. Level it out, and you get 36.

3 0
3 years ago
WILL GIVE BRAINLIEST Chang deposited $5000 into an account with a 4.8% annual interest rate, compounded monthly. Assuming that n
Mariulka [41]

Answer:

9.42 years (= 113 months)

Step-by-step explanation:

Use the compound rate interest formula:

A=P(1+\frac{r}{n})^{nt}

where:

  • A = amount
  • P = principal
  • r = interest rate (in decimal format)
  • n = number of times interest is compounded per unit t
  • t = time

Given:

  • A = $7850
  • P = $5000
  • r = 4.8% = 0.048
  • n = 12
  • t = years

\implies 7850=5000(1+\frac{0.048}{12})^{12t}

\implies 7850=5000(1.004)^{12t}

\implies \dfrac{7850}{5000}=(1.004)^{12t}

\implies 1.57=(1.004)^{12t}

Take natural logs:

\implies \ln1.57=\ln(1.004)^{12t}

\implies \ln1.57=12t\ln(1.004)

\implies t=\dfrac{\ln 1.57}{12 \ln1.004}

\implies t=9.42\textsf{ years (nearest hundredth)}

\implies t=113 \textsf{ months}

5 0
2 years ago
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