Ask question

Ask question

All categories

3 years ago

10

A car traveled 3⁄4 mile in one minute at constant speed. What was the speed of the car in miles per hour?

2 answers:

Vanyuwa [196]3 years ago

8 0

60 min = 1 hr

3/4 * 60 = mph (miles per hour)

3/4 * 60 = 45

The speed of the car in mph (miles per hour)

will be 45 mph

Answer = 45mph

Thank you for posting your question on Brainly!

We hope we can help you in the future!

As always I hope you have a great day!

zalisa [80]3 years ago

7 0

I think it should be 25 MPH

You might be interested in

I need how with plz

omeli [17]

Answer:

165 degrees

Step-by-step explanation:

According to the protractor, the angle stretches from 10 degrees to 175 degrees. Subtract 10 from 175 to get the total measurement, and you will get 165. The angle is 165 degrees.

6 0

2 years ago

Read 2 more answers

Math Middle School Question

Alenkinab [10]

You have to add the according numbers bcoz the a and b are just adding up
3+6 9

4 0

2 years ago

Read 2 more answers

I need help with this problem asap :(

Dafna1 [17]

Answer:

m<P=130°

m<Q=130°

m<R=50°

Step-by-step explanation:

m<P=130

m<Q=130

m<R=50

3 0

2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em /> $cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0

2 years ago

PLEASE HELP WITHIN 5 MINUTES! Be as accurate as possible!

Nookie1986 [14]

Answer:

2,75in

4,25in

33in²

Step-by-step explanation:

shorter base is 2,75in

larger base is 4,25in

S=11+10,5+9+2,5=33in²

8 0

2 years ago