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TiliK225 [7]
3 years ago
14

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer:

y - 1 = 3/2(x + 3)  last one

Step-by-step explanation:

sveticcg [70]3 years ago
4 0
(2,2)(-2,-4)
slope = (-4 - 2) / (-2 -2) = -6/-4 = 3/2. the slope of this line is 3/2. A parallel line will have the same slope

y - y1 = m(x - x1)
slope(m) = 3/2
(-3,1)...x1 = -3 and y1 = 1
now we sub
y - 1 = 3/2(x - (-3)....not done yet
y - 1 = 3/2(x + 3) <=== its the last one

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solniwko [45]

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Suzie's Nursery is having a sale on two kinds of plants, venus fly traps and bonsai trees.
ANTONII [103]

Answer:

Venus fly trap = 12

Bonsai tree = 17

Step-by-step explanation:

Given that :

Venus fly trap = $3per plant

Bonsai tree = $5 per plant

Number of plants sold = 29

Total cost of plant sold = $121

Let venus fly trap = x ; bonsai tree =y

x + y = 29 ___ (1)

3x + 5y = 121 ____(2)

From (1) :

x = 29 - y

In (2):

3(29 - y) + 5y = 121

87 - 3y + 5y = 121

87 + 2y = 121

2y = 121 - 87

2y = 34

y = 34/2

y = 17

x = 29 - 17

x = 12

Hence,

Venus fly trap = 12

Bonsai tree = 17

7 0
3 years ago
14<br> 10<br> 56<br> 40<br> 14<br> x<br> 56<br> find the length of the missing side
IrinaK [193]

Answer: 14x56=784

Step-by-step explanation:

4 0
3 years ago
Pls help :)) this question is confusing for me :)
Temka [501]

Given:

y^{2}(2 y-5)-8 y+20

To find:

The product of the expression.

Solution:

y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)

Take out -4 as a common factor in Last two terms.

                                =y^{2}(2 y-5)-4(2 y-5)

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

                                =(2 y-5)(y^{2}-4)

4 can be written as 2².

                                =(2 y-5)\left(y^{2}-2^2\right)

Using the identity: (a^2-b^2)=(a-b)(a+b)

                                =(2 y-5)(y-2)(y+2).

The product is (2 y-5)(y-2)(y+2).

5 0
3 years ago
A surf instructor has an initial fee of $12 and charges $8 per hour for lessons. Explain how to determine what the y-intercept i
Fittoniya [83]
At time t = 1 hr... fee is initial ($12)+ ($8) = 20<span><span>ribhu </span> 10 months ago</span>and so on... the intercept would be initial fee... which is $12 charged at t=0 hr
thats the best i can do

3 0
4 years ago
Read 2 more answers
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