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3 years ago

Is n=3 is a solution to the equation or 2n=6

Mathematics

2 answers:

dusya [7]3 years ago

7 0

Yes. Of coarse! (This text is here to fill in 20 characters.)

Triss [41]3 years ago

6 0

Opposite equation-->6/2
n=3
yes!

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Perform each indicated operation

MissTica

Answer: $\frac{x+6}{x-4}$

Step-by-step explanation:

First you need know some general formuals of factorization such as

$x^3+y^3=(x+y)(x^2-xy+y^2)$ so you have $x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)$

And, $x^2-y^2=(x-y)(x+y)$ so you have $2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)$

If you use them, then you can modify your equations such as

$\frac{x^3+64}{2x^2-32}$ ÷ $\frac{x^2-4x+16}{2x+12}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)}$ ÷ $\frac{x^2-4x+16}{2(x+6)}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} . \frac{2(x+6)}{{x^2-4x+16}} = \frac{1}{x-4}.\frac{x+6}{1}=\frac{x+6}{x-4}$

4 0

3 years ago

Springboard Geometry Chapter 21 Mid-Unit Assessment

ExtremeBDS [4]

I really don't know just say its o

4 0

3 years ago

Write an equation in slope-intercept form of the line that passes through <br> (7, 2) and (2, 12).

Gnoma [55]

Answer:

Step-by-step explanation:

(12 - 2)/(2 - 7) = 10/-5 = -2

y - 12 = -2(x - 2)

y - 12 = -2x + 2

y = -2x + 14

6 0

3 years ago

We want to find the zeros of this polynomial p(x)= ( x^2-1)(x^2-5x+6)

Scrat [10]

Answer:

see explanation

Step-by-step explanation:

To find the zeros let p(x) = 0 , that is

(x² - 1)(x² - 5x + 6) = 0

Factorise each factor

x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)

x² - 5x + 6 = (x - 2)(x - 3), thus

(x - 1)(x + 1)(x - 2)(x - 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x + 1 = 0 ⇒ x = - 1

x - 2 = 0 ⇒ x = 2

x - 3 = 0 ⇒ x = 3

The zeros are x = ± 1, x = 2, x = 3

4 0

3 years ago

If the original length are multiple by 1/3 what are the new coordinates

Olenka [21]

Answer:

Step-by-step explanation:

7 0

3 years ago