Answer:
Please see attached graph.
Step-by-step explanation:
The equations for straight lines are given as:
i) y = x +4
ii) y= x-4
Yon can form a table for values of x and y that are true for an equation and use these values as coordinates ( x,y ) to plot the graphs and view the lines to select the correct labels for the equations.
For i)
y= x+4
x y coordinates
-3 1 (-3,1 )
-2 2 (-2,2)
-1 3 (-1,3)
0 4 ( 0,4)
1 5 ( 1,5)
2 6 ( 2,6)
3 7 ( 3,7)
Plot the points on a graph tool and draw the line. Do the same for the second equation to view both graphs as shown in the attached graph.
C!!!!!!!!!!!!!!! Hope I’m right
Step-by-step explanation:
Quotient of 2/3 divided by 4
= (2/3) / 4
= 2/12
= 1/6.
PLZ HELP IVE BEEN WAITING FOR 1HR : <span>A rectangular prism has a length of 8 in., a width of 4 in., and a height of 2 1/4 in.
The prism is filled with cubes that have edge lengths of 1/4 in.
How many cubes are needed to fill the rectangular prism?</span>
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.
2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.
3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.
4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.
Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
