√x+3 = 2
First we should simplify the equation by squaring both sides:
x + 3 = 4
Isolate x by taking 3 off both sides:
x = 1
We should ALWAYS check that our answer is correct after working out the value of x. We can do this by substituting x into the original equation:
√x + 3 = 2
Turns into:
√1 + 3 = 2
Which turns into:
√4 = 2
Which is true, therefore we can confirm:
x = 1
If s(t) = 3 sin(2 (t - π/6)) + 5, then the derivative is
s'(t) = 3 cos(2 (t - π/6)) • 2 = 6 cos(2 (t - π/6))
The critical points of s(t) occur at the values of t where s'(t) is zero or undefined. s'(t) is continuous everywhere, so we only need worry about the first case. We have
6 cos(2 (t - π/6)) = 0
cos(2t - π/3) = 0
2t - π/3 = arccos(0) + nπ
(where n is any integer)
2t - π/3 = π/2 + nπ
2t = 5π/6 + nπ
t = 5π/12 + nπ/2
If you're only looking for t in the interval [0,2π), then you have four critical points at t = 7π/12, t = 11π/12, t = 17π/12, and t = 23π/12.
Answer:
Constant
Step-by-step explanation:
For a straight line for example,
Take any two points from the line and find the slope,
it will be the same value for any 2 points chosen
So throughout the graph, the slope/rate of change is not changing
That is
Throughout the graph rate of change/slope is constant
Answer:
Simply subtract the fail rate from 100; the resulting number is the pass rate. So, if you know that 6 percent of students failed, you would subtract: 100 - 6 = 94 percent is the pass rate for the test.
Step-by-step explanation:
