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Eddi Din [679]
3 years ago
10

The sum of the digits of a two-digit number is 7. the new number obtained when the digits are reversed is 27 less than the origi

nal number. find the original number
Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0
We can figure this out by finding all the combinations:
 0 + 7 = 7 (07)
1 + 6 = 7 (16)
2 + 5 = 7 (25)
3 + 4 = 7 (34)
4 + 3 = 7 (43)
5 + 2 = 7 (52)
6 + 1 = 7 (61)
7 + 0 = 7 (70)

Obviously 70 can't be our number, as it would be a one digit number, 

Since we're going down in value ( 27 less ) our original number will be a larger number.

52 reversed is 25 which is 27 less than 52.

Our original number is 52 here.

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Simplify by performing long division.
olga_2 [115]

Answer:

the answer is A. 3x-2+2/x+1

3 0
2 years ago
Christen sells boxes of cookies for $4 each. Rafael sells boxes of cookies for $7 each. Each of them sold the same dollar amount
KATRIN_1 [288]

Answer:

28$ and christen sold 7 boxes while Rafael sold 4

Step-by-step explanation:

lower common multiple so take 4 x 7 = 28 as then take the 28 and divide by how much Christen gets a box which is 4 and 28 divided by 4 is 7

3 0
3 years ago
Read 2 more answers
Question: A canary's beak is, at most, 20mm long. Which algebraic inequality represents this situation?
Paul [167]

Answer:

Option (1).

Step-by-step explanation:

Statement given states that "A canary's beak is, at most 20 mm long."

Word "at most" means "the maximum".

So at most length of the beak means "length of the beak is less than equal to 20 mm".

And the expression representing this statement algebraically will be,

x ≤ 20

Therefore, option (1) will be the correct option.

8 0
2 years ago
Selina didn't use the distributive property correctly. Where did she go wrong? Explain your thinking.​
GarryVolchara [31]

Answer:

PEMDAS

Step-by-step explanation:

Well, I don't know if there should be a picture of the problem that should go with the question. But a trick for solving distributive property is to use the trick PEMDAS In order.

For Example:

P-Paraenthese

E-Exponent

M-Multiply

D-Divide

A-Add

S-Subtract

NOTE!

Remember to always Multiply and divide BEFORE adding and subtracting.

Hoped this helped!

6 0
3 years ago
Tính : <br>a) (a+b+c)^2<br>b) (a-b-c)^2<br>c) (a+b-c)^2<br>d) (a-b+c)^2
LiRa [457]

Answer:

a.) a² + b² + c ² + 2ab + 2ac + 2bc

b.) a² + b² + c² - 2ab - 2 ac + 2bc

c ) a² + b² + c² + 2ab - 2ac - 2bc

d.) a² + b² + c² - 2ab + 2ac - 2bc

Step-by-step explanation:

  • Use ( a + b + c )² = a² + b² + c² + 2 × ab + 2 × ac + 2 × bc to expand all these expression

a) ( a + b + c )²

= a² + b² + c² + 2 × ab + 2 × ac + 2 × bc

= a² + b² + c ² + 2ab + 2ac + 2bc

b.) ( a - b - c )

= a² + ( - b )² + ( - c)² + 2a ( -b ) + 2a(-c) + 2(-b)(-c)

= a² + b² + c² - 2ab - 2 ac + 2bc

c.) ( a + b - c )²

= a² + b² + ( -c)² + 2ab + 2a ( - c) + 2 b( -c)

= a² + b² + c² + 2ab - 2ac - 2bc

d.) (a - b + c ) ²

= a² + ( -b)² + c² + 2a(-b) + 2ac + 2c( -b)

= a² + b² + c² - 2ab + 2ac - 2bc

3 0
2 years ago
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