Answer:
x
≤
13
Step-by-step explanation:
hope this helps
1. 1 7/8
wait a minute for me to answer number 2
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
3.4028 x 10^-1
Step-by-step explanation:
First you make the 9400 into scientific notation:
9.4x10^3
Then you combine like terms
(3.62x9.4)(10^-5x10^3)
Finally you simplify
34.028x10^-2
3.4028x10^-1
