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ratelena [41]
3 years ago
14

A movie theater charges $5 per ticket and averages 300 customers each night. If prices are raised to $7 per ticket, the theater

estimates that average nightly ticket sales will be $1,750. What is the percentage change in the average number of customers the theater has each night? (Express your answer in whole numbers; round decimals up or down).
Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0

Attendance with the higher ticket price is ...

... $1750/$7 = 250

So the percentage change in attendance is ...

... change = (new - original)/original × 100%

... = (250 -300)/300 × 100% = -1/6×100% ≈ -17%

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Answer:

  both kinds of tickets are $5 each

Step-by-step explanation:

Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:

  12s + 5c = 85 . . . . . revenue from the first day of sales

  6s + 9c = 75 . . . . . . revenue from the second day of sales

Double the second equation and subtract the first to eliminate the s variable.

  2(6s +9c) -(12s +5c) = 2(75) -(85)

  13c = 65 . . . . . simplify

  65/13 = c = 5 . . . . . divide by the coefficient of c

Substitute this value into either equation. Let's use the second one.

  6s + 9·5 = 75

  6s = 30 . . . . . . . subtract 45

  30/6 = s = 5 . . . divide by the coefficient of s

The price of a senior ticket is $5; the price of a child ticket is $5.

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