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3 years ago

Is seventy five thousandths less than, greater than or equal to 0.75

Mathematics

2 answers:

ryzh [129]3 years ago

6 0

Seventy five thousandths is less than .75

AleksandrR [38]3 years ago

5 0

Is less than 0.75 because you say that 0.075 is greater than or equal to 0.75.

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How to check division with multplication <img src="https://tex.z-dn.net/?f=3%20%5Ctimes%20292%20" id="TexFormula1" title="3 \

svetoff [14.1K]

Answer: By cross multiplication.

Step-by-step explanation: Given product is 3 × 292.

We know that after simple multiplication, we get 3 × 292 = 876.

Now, to check division with multiplication, either we need to divide 876 by 3 to get the answer 292,

we need to divide 876 by 292 to get the answer 3.

We will do that as follows -

$\dfrac{876}{3}=292~~~\textup{and}~~~\dfrac{876}{292}=3.$

Thus, doing cross-multiplication, we arrive at our conclusion.

6 0

3 years ago

3) 14 pennies to 35 pennies

Leno4ka [110]

Answer:

Step-by-step explanation:

14/35

Find the GCD of numerator and denominator

GCD of 14 and 35 is 7

Divide both the numerator and denominator by the GCD

14 ÷ 7

35 ÷ 7

2/5

I'm always happy to help :)

5 0

3 years ago

6th grade math Help plz

irina1246 [14]

How do you say that having any confusion he said wouldn’t be able to consist of all the new stages

8 0

3 years ago

I need help on this.. First person to answer this correctly gets a BRANLIST

arlik [135]

Answer: The relation is a function.

Step-by-step explanation: Since there is one value of y for every value of x in (-2,4), (3,7), (0,8), (5,8), and (1,6), this relation is a function.

I hope this helps you out!

7 0

3 years ago

D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago