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3 years ago

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The table shows the number of each type of toy in a store. The toys will be placed on shelves so that each shelf has the same nu

mber of each type of toy. How many shelves are needed. For each type of toy so thay it has the greatest number of toys? Table: 45, 105, 75

1 answer:

puteri [66]3 years ago

7 0

Hai! You're gonna need 15 shelves for all those toys. X)

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Carpet sells for $3 per square foot and will cost you $810 to recarpet your rectangular room. if your room is 18 feet long, how

raketka [301]

$810 ÷ 3 = 270 square feet
Area of the room is 270 square feet.

Area = 270 square feet, length = 18 feet

Area = Length x Width
270 = 18 x width
Width = 280 ÷ 18
Width = 15 feet

The room is 15 feet wide.

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2 years ago

**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?

Nina [5.8K]

We analyze the chart and observe that the linear function is $y=x$ , since this relation holds for all values in the table. Drawing this line over the quadratic function shows that they intersect twice, at both the positive and negative x-coordinates.

This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on! To prove this more rigorously, we can find that the equation of the parabola is $y=\frac13 x^2 - 2.$ Substituting in $y=x$ , we find that the intersection points occur where $\frac13 x^2 - 2 = x$ , or $\frac13 x^2 - x - 2 = 0,$ or $x^2 - 3x - 6 = 0.$

This equation doesn't factor nicely, so we use the quadratic formula to learn that $x = \frac{3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-6)}}{2} = \frac{3 \pm \sqrt{33}}{2}.$ Hence, the x-coordinates of the intersection points are $\frac{3 + \sqrt{33}}{2}$ , which is positive, and $\frac{3 - \sqrt{33}}{2}$ , which is negative. This proves that there are intersection points on both ends of the axis.

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3 years ago

Can 9 40 41 make a triangle

maksim [4K]

Answer:

yes

Step-by-step explanation:

Hi there!

We want to see if 9, 40, and 41 can be the sides of a triangle that can exist

We can use triangle inequalities to figure that out

For triangle inequalities, if the lengths of the sides are a, b, and c, then a+b>c, b+c>a, and c+a>b, then the lengths can make a triangle
Let's say that a=9, b=40, and c=41

Now substitute these values into the inequalities:

a+b>c

9+40>41

49>41

This is a true statement.

b+c>a

40+41>9

81>9

This is also a true statement.

41+9>40

50>40

This is a true statement as well.

Since all three of the inequalities ended up being true (all three NEED to be true in order for the given lengths to make a triangle), then we can confirm that 9, 40, and 41 can make a triangle

Hope this helps!

See more on this topic here: brainly.com/question/17357347

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2 years ago

Write a number that rounds to 2.3 when rounded to the nearest hundredth and when rounded to the nearest tenth, but does not roun

tatuchka [14]

Answer:

2.3011

Step-by-step explanation:

This is because if you round this to the nearest tenth, the digit is 0 so it stays the same. When you round to the nearest hundredth, you would look at the 1 in the thousandth place and know that it is less than 5 so you would round down to 2.3. When you round to the nearest thousandth place, you would look at the very last number, which is less than 5, round down to 2.301 and realize that it is not equivalent to 2.3 :) I hope this helps

3 0

3 years ago

Read 2 more answers

Helppp plssss!!!!<br><br>Thanks

Ket [755]

Answer: the answer is D

Step-by-step explanation: this is because every time an hour passes its multiplied by $49.00 but $85 is a fixed feee so the x would bethe hour making the last answer correct

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3 years ago