Complete Question:
Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.
Answer:

Step-by-step explanation:
<em>See comment for complete question</em>
Given


Required
Determine how they can show if the products are the same or not
To do this, we simply factorize each polynomial
For, Polynomial A: We have:

Factor out 4x

Apply difference of two squares on x^2 - 4

For, Polynomial B: We have:

Expand x^2 + x - 2

Factorize:

Factor out x + 2

Factor out 4x

Rearrange

The simplified expressions are:
and

Hence, both polynomials are equal

<span>of the task , we know that :
</span>
profit netto = $ 6100
<span>influenza students = 7
</span>hourly rate for one lesson of the French language = $45
<span>we do not know about
</span>
profit brutto = ? <span>denoted as x
</span><span>the amount collected lessons
for one student = ? denoted as y
x = $6100 + $200
</span>

<span>
</span>

<span>
2 away
</span>

<span>
</span>
Answer:
A'(7,-3)
Step-by-step explanation:
We were given the coordinates, A(-7,3) of quadrilateral ABCD and we want to find the image of A after a reflection across the x-axis followed by a reflection in the y-axis.
When we reflect A(-7,3) across the x-axis we negate the y-coordinate to obtain: (-7,-3).
When the image is again reflected in the across the y-axis, we negate the x-coordinate to get (--7,-3).
Therefore the coordinates of A' after the composed transformation is (7,-3).