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Zarrin [17]
2 years ago
14

Help me plz i need the answer ? :)

Mathematics
1 answer:
lianna [129]2 years ago
8 0

Answer:

D

Step-by-step explanation:

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What is it the formula for calculating volume of a rectangular prism?
taurus [48]

Answer:

idk

Step-by-step explanation: took test

6 0
3 years ago
Read 2 more answers
Round 3:38 to the nearest ten
aev [14]

Answer:3

Step-by-step explanation:

Round 3.38 to the nearest ten

Rounding up to the nearest 10, we look at the digits on the left hand side of the decimal point. If the number on the right of the decimal point is less than 5, we ignore it.if it is greater than 5, we add one to the last digit on the right hand side.

In this case, the first digit on the left hand side is less than 5, so we ignore it. Rounding up to the nearest ten,the 0.38 is ignored.

Therefore, it becomes 3.0 = 3

To the nearest ten

7 0
3 years ago
.
timofeeve [1]
A=9,805×(1+0.085×7÷12)
A=10,291.16
7 0
3 years ago
If five times the successor of a number is added to an original number the sum is 83
Alexus [3.1K]

Answer:

Let the original number be x

Successor is defined as the number which comes immediately after a particular number.

also, the  successor of a whole number is the number obtained by adding 1 to that number.

Then, the successor of a number x is, x+1

As per the given condition :

we have;

5(x+1)+x =83

Using distributive property on LHS (i.e, a\cdot(b+c)=a\cdot b+a\cdot c )

Then, we have

5x+5+x=83

Combine like terms;

6x+5=83

Subtract 5 from both the sides we get;

6x+5-5=83-5

Simplify:

6x=78

Divide both side by 6,

\frac{6x}{6} =\frac{78}{6}

Simplify:

x =13

Therefore, the original number x is, 13


8 0
3 years ago
1/2 ln(x + 3) - lnx = 0 solve for x
rusak2 [61]
1

 

Simplify \frac{1}{2}\imath n(x+3)​2​​1​​ın(x+3) to \frac{\imath n(x+3)}{2}​2​​ın(x+3)​​

\frac{\imath n(x+3)}{2}-\imath nx=0​2​​ın(x+3)​​−ınx=0


2

 

Add \imath nxınx to both sides

\frac{\imath n(x+3)}{2}=\imath nx​2​​ın(x+3)​​=ınx


3

 

Multiply both sides by 22

\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2


4

 

Regroup terms

\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı


5

 

Cancel \imathı on both sides

n(x+3)=nx\times 2n(x+3)=nx×2


6

 

Divide both sides by nn

x+3=\frac{nx\times 2}{n}x+3=​n​​nx×2​​


7

 

Subtract 33 from both sides

x=\frac{nx\times 2}{n}-3x=​n​​nx×2​​−3


6 0
3 years ago
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