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Alekssandra [29.7K]
3 years ago
7

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a blue chip not replacing it,

and then randomly choosing another blue chip?
Mathematics
2 answers:
inessss [21]3 years ago
8 0

Answer: \dfrac{7}{15}

Step-by-step explanation:

Given : The number of blue chips in the bag = 7

The number of gold chips in the bag = 3

Total number of chips : 7+3=10

Now, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip is given by :-

\dfrac{6\times7}{9\times10}=\dfrac{7}{15}

Hence,  the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip =\dfrac{7}{15}

spayn [35]3 years ago
5 0

Answer:

7/10 × 6/9 = 42/90 = 7/15

Step-by-step explanation:

so theres 10 chips total.

on the first draw there 7 blue chips and a total of 10 chips of both colors

take one away from the 7 chips we have and get 6 over the 9 chips.

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36a^2+24b^2=12( +2b^2)
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3 years ago
What is the 214 term in the sequence 7,10,13,16?
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We can figure this out using the explicit formula.

f(n)=f(1)+d(n-1)

n represents the term we are looking for.
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d represents the common difference, which in this case, is +3.

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The 214th term in this sequence is 646.
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3 years ago
The point (-7,4) is reflected over the line x=-3. Then the resulting point is reflected over the line y=x. Where is the point lo
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