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Alekssandra [29.7K]
2 years ago
7

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a blue chip not replacing it,

and then randomly choosing another blue chip?
Mathematics
2 answers:
inessss [21]2 years ago
8 0

Answer: \dfrac{7}{15}

Step-by-step explanation:

Given : The number of blue chips in the bag = 7

The number of gold chips in the bag = 3

Total number of chips : 7+3=10

Now, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip is given by :-

\dfrac{6\times7}{9\times10}=\dfrac{7}{15}

Hence,  the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip =\dfrac{7}{15}

spayn [35]2 years ago
5 0

Answer:

7/10 × 6/9 = 42/90 = 7/15

Step-by-step explanation:

so theres 10 chips total.

on the first draw there 7 blue chips and a total of 10 chips of both colors

take one away from the 7 chips we have and get 6 over the 9 chips.

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Door prizes for entrants in a young inventors competition are $100, $50, $25 and $10. In how many ways can the door prizes be aw
Over [174]

The total number of ways the prizes are awarded is 8855.

The prizes for entrants in a young inventors competition are $100, $50, $25, and $10.

Which are of total 4 types of prizes.

If there are 23 entrants in the competition the prizes can be awarded in the following ways by using Combinations.

Total number of ways =  ²³C₄

                                    = \frac{23!}{4! * (23 - 4)!}

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The total number of ways the prizes are awarded is 8855.

To learn more about Combinations click here:

brainly.com/question/13387529

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8 months ago
9(n+3)=7n-3 and steps please
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