Question

Suppose a bag contains 7 blue chips and 3 gold chips. What is the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip?

Answer 1

Answer: $\dfrac{7}{15}$

Step-by-step explanation:

Given : The number of blue chips in the bag = 7

The number of gold chips in the bag = 3

Total number of chips : 7+3=10

Now, the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip is given by :-

$\dfrac{6\times7}{9\times10}=\dfrac{7}{15}$

Hence,  the probability of randomly choosing a blue chip not replacing it, and then randomly choosing another blue chip $=\dfrac{7}{15}$

Answer 2

Answer:

7/10 × 6/9 = 42/90 = 7/15

Step-by-step explanation:

so theres 10 chips total.

on the first draw there 7 blue chips and a total of 10 chips of both colors

take one away from the 7 chips we have and get 6 over the 9 chips.