Answer:
The logarithmic function, , is spoken as "the log, base a, of x." The logarithmic function is the inverse of the exponential function, so one can also think of logarithms by using exponential form. is the same operation as thinking "a to the y power equals x." The common logarithmic function, written y = log x, has an ...
The answer is x= - 11/ 16
You can check this by plugging in x for -11/16
VK = VY+YK by the segment addition postulate. Basically adding two segments along a straight line forms a longer segment. In this case, VY and YK combine to form VK
Since VK = x and VY = 22, this means...
VK = VY+YK
x = 22+YK
x-22 = YK
YK = x-22
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Notice the arc marks where the point T is located. These markings tell us that the two angles VTY and YTK are congruent angles. Because of this, we can use the angle bisector theorem which says that the ratio of the corresponding sides are congruent.
In short, we can form this ratio
VT/VY = KT/KY
which is the ratio of the side adjacent to the angle, to the side opposite the angle
Plug in the given values and solve for x
VT/VY = KT/KY
77/22 = 87.5/(x-22)
77(x-22) = 22*87.5
77(x-22) = 1925
77x-77*22 = 1925
77x-1694 = 1925
77x = 1925+1694
77x = 3619
x = 3619/77
x = 47
Answer: 47
Answer:
You can use this step to answer your question
Step-by-step explanation:
he vector projection of #vecu# onto #vecv# is
#=(vecu.vecv)/(||vecv||^2)*vecv#
The dot product is
#vecu.vecv=<3,15>.<-1,5>=-3+75=72#
The modulus of #vecv# is
#||vecv||=||<-1,5>||=sqrt(1+25)=sqrt26#
The vector projection is
#=72/26<-1,5> = 36/13<-1,5>#
The scalar projection is
#(vecu.vecv)/(||vecv||)=72/sqrt26#