Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:
![K=\frac{mv^2}{2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7Bmv%5E2%7D%7B2%7D)
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
![2*K=\frac{mv^2}{2}*2](https://tex.z-dn.net/?f=2%2AK%3D%5Cfrac%7Bmv%5E2%7D%7B2%7D%2A2)
![2K=mv^2](https://tex.z-dn.net/?f=2K%3Dmv%5E2)
Divide by m to isolate
.
![\frac{2K}{m}=\frac{mv^2}{m}](https://tex.z-dn.net/?f=%5Cfrac%7B2K%7D%7Bm%7D%3D%5Cfrac%7Bmv%5E2%7D%7Bm%7D)
![\frac{2K}{m} =v^2](https://tex.z-dn.net/?f=%5Cfrac%7B2K%7D%7Bm%7D%20%3Dv%5E2)
To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
0.06 or you can just put 6.
Basically, you have to multiply 30% x 20.
Glad I could help☺️
subtract 3 from 23 and u will get 20 then divide 2 by 2 and 2 by 20
x= 10
Umm if it’s wrong I’m sorry but I think it’s D!!