In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m). The relation of speed (v), distance (d), and time (t) can be expressed as: v = d/t
We need to calculate the speed of the second 5 seconds of the travel: d = 20 m (total 30 meters - first 10 meters) t = 5 s (time from t = 5 seconds to t = 10 seconds)
<span><span>A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel
20miles / 5sec = 4miles /sec would be the average speed for the last 20 min</span><span> </span></span>
The answer is 58, standard deviation is basically telling you that the space between each point in your statistics is on average that amount so that can tell us to take the mean mark of 55 and add 2.85 = 57.85
For the answer to the question above, w<span>hat are the dimensions of the park on the scale drawing? </span>If you divide 25 by 50 you get .5 and if you divide 100 by 50 you get 2. So I would divide 600 by 50 = 12 inches and 1000 by 50 = 500 inches. So the answer is 12 x 20 inches
