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Answer:
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)
Step-by-step explanation:
1.
The denominator of f is defined for all real values of x
Therefore, the function is continuous on the set of real numbers
3.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function h is defined for all real values.
2.
The denominator of g is defined for all real values of x.
Therefore, the function g is continuous on the set of real numbers
4.
x-9=0
x=9
The function i is not defined for x=9
Therefore, the function i is not continuous on the set of real numbers.
5.
The denominator of j is defined for all real values of x.
Therefore, the function j is continuous on the set of real numbers.
6.
It cannot be factorize .
Therefore, it has no real values for which it is not defined .
Hence, function k is defined for all real values.
7.
The function is not defined for x=8 and x=1
Hence, function l is not defined for all real values.
8.
The denominator of m is defined for all real values of x.
Therefore, the function m is continuous on the set of real numbers.
g(x)<j(x)<k(x)<f(x)<m(x)<h(x)
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Answer:
(5, 6) is (h, k)
Step-by-step explanation:
Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).
Parent:
f(x) = x^2
Transformed:
f(x) = a(x -h)^2 +k
__
When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...
- a = 2
- -h = -5 ⇒ h = 5
- k = 6
Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.
The critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
<h3>How to determine the critical values corresponding to a 0.01 significance level?</h3>The scatter plot of the election is added as an attachment
From the scatter plot, we have the following highlights
- Number of paired observations, n = 8
- Significance level = 0.01
Start by calculating the degrees of freedom (df) using
df =n - 2
Substitute the known values in the above equation
df = 8 - 2
Evaluate the difference
df = 6
Using the critical value table;
At a degree of freedom of 6 and significance level of 0.01, the critical value is
z = 0.834
From the list of given options, 0.834 is between -0.881 and 0.881
Hence, the critical values corresponding to a 0.01 significance level used to test the null hypothesis of ρs = 0 is (a) -0.881 and 0.881
Read more about null hypothesis at
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Answer:
c.
Step-by-step explanation:
* To make this simpler, reduce these two fractions in lowest terms.
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