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3 years ago

How to find the solution of |a-4|=3a-6

1 answer:

6 0

For
|a|=b, solve for
a=b and a=-b

so

|a-4|=3a-6
solve
a-4=3a-6 and a-4=-(3a-6)

first one
a-4=3a-6
minus a from both sides
-4=2a-6
add 6 to both sides
2=2a
divide by 2
1=a

other

a-4=-(3a-6)
a-4=-3a+6
add 3a both sides
4a-4=6
add 4 to both sides
4a=10
divide by 4
a=10/4
a=5/2

a=5/2 and 1

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use the order of operations to simplify this expression. exspress your answer in the simplest form. 1/4 + 1/2 ÷ 2/8

elixir [45]

Answer:

9/4

Step-by-step explanation:

This is quite simple you do 1/2 divided by 2/8 which will become multiplication. Then its that number plus 1/4

you get a answer of

9/4 in fraction form

2.25 in decimal form

2 1/4 in mixed fraction form

7 0

2 years ago

The surface are I cannot find

Ilia_Sergeevich [38]

check the picture below.

so the triangular prism is really just 3 rectangles and 2 right-triangles,

now, we know the base of one of the triangles is 2.6, what's its height?

since it's a right-triangle, we can simply use the pythagorean theorem to get "h".

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad
\begin{cases}
c=\stackrel{hypotenuse}{5.2}\\
a=\stackrel{adjacent}{2.6}\\
b=\stackrel{opposite}{h}\\
\end{cases}
\\\\\\
\sqrt{5.2^2-2.6^2}=h\implies 4.5\approx h$

so, we can now, simply get the area of both of the triangles and the three rectangles and sum them up, and that's the area of the triangular prism.

$\bf \stackrel{two~triangles}{2\left[ \cfrac{1}{2}(2.6)(4.5) \right]}~~+~~\stackrel{rectangle}{(2.6\cdot 4.3)}~~+~~\stackrel{rectangle}{(4.3\cdot 3.9)}~~+~~\stackrel{rectangle}{(4.3\cdot 5.2)}
\\\\\\
11.7+11.18+22.36\implies \blacktriangleright 45.24 \blacktriangleleft$

5 0

3 years ago

Read 2 more answers

A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated

zysi [14]

Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)

8 0

3 years ago

Miss Smith save 5% on her recent Starbucks order because she is a Starbucks Rewards member if the cost of per purchase before th

Dima020 [189]

It would have been $5.48

4 0

3 years ago

Read 2 more answers

The sum of two numbers is 62, and their difference is 8. What are the numbers

Lemur [1.5K]

Sum of two numbers is 62?
Let's call the two numbers $a$ and $b$

let's find two same numbers that would add up to 62: 31.
31 + 31 = 62

since it said the difference is 8, we have to add 4 to one number and subtract 4 from another.
31 - 4 = 27
31 + 4 = 35

Therefore, the two numbers following the given rules are 27 and 35

7 0

3 years ago