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3 years ago

The sides of this rectangle are

Mathematics

1 answer:

Naddik [55]3 years ago

8 0

The longer side is at first 7cm and the shorter is 2cm.

So since 7cm(the longer side)×5=35cm then the shorter side(2cm) multiplied by 5 should give you the right answer.

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Different shapes are drawn on cards and then the cards are placed in a bag. The number of cards for each shape is shown in the t

Verdich [7]

This question was posted almost a week ago, and I am not sure if you still need the answer, but I'll explain it.

The total number of all of the shapes were placed in the bag are equal to 100. The number comes from adding 32+20+48=100.
This is our total number and will be the denominator.
There are a total of 32 cards which have a hexagon, this number will be our numerator.

So far we have 32/100 , but this is not simplest form.

Next to reduce the fraction, the GCF must be found.

32: 1, 2, 4, 8, 32
100: :

8 0

3 years ago

a dollhuse has a bed with diemesions 1/12 size of a queen size bed has an area of 4,800 square inches, and a length of 80 inches

aliina [53]

Divid to get the other side :) so if the doll house is 1/12 of the queen size bed you divid each side by 12 see. 4800/80=60. 80/12=6.6667.... so 60/12=5. so then 5x6 1/3. hope this helps you ... goood luck! :)

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3 years ago

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inn [45]

Answer:

Yea sure.

Step-by-step explanation:

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3 years ago

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30 POINTS!!! HELP!!!! Which function best models the data in the table?

PSYCHO15rus [73]

Answer:

John Felix Anthony Cena is an American professional wrestler, actor, and television presenter. He is currently signed to WWE. Born and raised in West Newbury, Massachusetts, Cena moved to California in 1998 to pursue a career as a bodybuilder.

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4 0

3 years ago

A metal beam was brought from the outside cold into a machine shop where the temperature was held at 65degreesF. After 5 min, t

ivolga24 [154]

Answer:

The beam initial temperature is 5 °F.

Step-by-step explanation:

If T(t) is the temperature of the beam after t minutes, then we know, by Newton’s Law of Cooling, that

$T(t)=T_a+(T_0-T_a)e^{-kt}$

where $T_a$ is the ambient temperature, $T_0$ is the initial temperature, $t$ is the time and $k$ is a constant yet to be determined.

The goal is to determine the initial temperature of the beam, which is to say $T_0$

We know that the ambient temperature is $T_a=65$ , so

$T(t)=65+(T_0-65)e^{-kt}$

We also know that when $t=5 \:min$ the temperature is $T(5)=35$ and when $t=10 \:min$ the temperature is $T(10)=50$ which gives:

$T(5)=65+(T_0-65)e^{k5}\\35=65+(T_0-65)e^{-k5}$

$T(10)=65+(T_0-65)e^{k10}\\50=65+(T_0-65)e^{-k10}$

Rearranging,

$35=65+(T_0-65)e^{-k5}\\35-65=(T_0-65)e^{-k5}\\-30=(T_0-65)e^{-k5}$

$50=65+(T_0-65)e^{-k10}\\50-65=(T_0-65)e^{-k10}\\-15=(T_0-65)e^{-k10}$

If we divide these two equations we get

$\frac{-30}{-15}=\frac{(T_0-65)e^{-k5}}{(T_0-65)e^{-k10}}$

$\frac{-30}{-15}=\frac{e^{-k5}}{e^{-k10}}\\2=e^{5k}\\\ln \left(2\right)=\ln \left(e^{5k}\right)\\\ln \left(2\right)=5k\ln \left(e\right)\\\ln \left(2\right)=5k\\k=\frac{\ln \left(2\right)}{5}$

Now, that we know the value of $k$ we can use it to find the initial temperature of the beam,

$35=65+(T_0-65)e^{-(\frac{\ln \left(2\right)}{5})5}\\\\65+\left(T_0-65\right)e^{-\left(\frac{\ln \left(2\right)}{5}\right)\cdot \:5}=35\\\\65+\frac{T_0-65}{e^{\ln \left(2\right)}}=35\\\\\frac{T_0-65}{e^{\ln \left(2\right)}}=-30\\\\\frac{\left(T_0-65\right)e^{\ln \left(2\right)}}{e^{\ln \left(2\right)}}=\left(-30\right)e^{\ln \left(2\right)}\\\\T_0=5$

so the beam started out at 5 °F.

6 0

4 years ago