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Bas_tet [7]
3 years ago
8

A right square pyramid has a slant height of 13 inches and a lateral area of 260 square inches. What is the volume of the pyrami

d to the nearest cubic inch?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

I believe you multiply the 2 numbers, then divide by two

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Slope=5, goes through the point (2,7) what is the answer
Sidana [21]

Answer:

slope-intercept form: y=5x-3 point-slope form: y-7=5*(x-2)

Step-by-step explanation:

Y-y1=m(x-x1)

plug in the values and you get y=5x-3

7 0
2 years ago
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Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
( I NEED THIS ANSWERED SUPER FAST IM ON A DEADLINE HELP ME!!!)
r-ruslan [8.4K]
The answer to the question is 9/45, 8/40
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A baby weighed 7.25 lb at birth. At the end of 8 months, the baby weighed 2.5 times its birth weight. How many pounds did the ba
Vesnalui [34]

Answer: 18.125 lbs

Explanation: The baby weighed 18.125 pounds at the end of eight months.

The baby weighed 7.25 lbs at birth. Eight months later, he weighed 2.5 or 2½ times its birth weight. Multiply 7.25 by 2.5  (which equals 18.125).

So now eight months later, he's 18.125 pounds.

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Use the graphing calculator to determine the interval on which the inequality log2 (0.7x) log3(3x – 1) is true. Round any decima
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Answer:

[0.373, 16.607]

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