Answer:
they would get somewhere from 80% to 85%
Step-by-step explanation:
Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.


We have,

Introduce variable
such that 
The sum
is therefore 
So,
(sadia's age)
(father's age)
Hope this helps :)
Answer:
3375
Step-by-step explanation:
Answer:
x > -21/4
Step-by-step explanation: