Answer:
1/10 per sec
Step-by-step explanation:
When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent
tanΘ = x/18
Taking the derivative with respect to time
sec²Θ dΘ/dt = 1/18 dx/dt.
He's walking at a rate of 18 ft/sec, so dx/dt = 18.
After 3seconds,
Speed = distance/time
18ft/sec =distance/3secs
x = 18 ft/sec (3 sec)
= 54ft. At this moment
tanΘ = 54/18
= 3
sec²Θ = 1 + tan²Θ
1 + 3² = 1+9
= 10
So at this moment
10 dΘ/dt = (1/18ft) 18 ft/sec = 1
10dΘ/dt = 1
dΘ/dt = 1/10 per sec
Answer:
CORRECT OPTION is (C) The flight will be late on one of the three days.
Step-by-step explanation:
The 7am flight from Dallas to Chicago is on time 75% of the time.
A spinner with four sections was created by Fran to simulate this scenario.
Since the 4 sections were equal, it means each section was 25% of the spinner.
3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.
This coincides with the 75% probability that the flight is on time on a given day.
In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.
Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:
- Shaded - Shaded - Unshaded
CORRECT OPTION is (C) The flight will be late on one of the three days.
One solution could be:
2/7 + 3/7 = 5/7
Another could be:
4/14 + 6/14 = 10/14 = 5/7
If you skip a warm up, you increase the greater change of oxygen dept.
Hope this helps!
@SamSamySamantha!
Answer:
Can you maybe elaborate the question with the help of brackets I guess ...?
It is difficult to understand the question this way .
