Answer:
a. True, b. False, c.True, d. True
Explanation:
a. Base excision repair is started by a DNA glycosylase that recognizes the changes and removes the altered base by cleavage of the glycosidic bond binding the base and the deoxyribose sugar together.
b. Nucleotide excision repair works by a cut-and patch mechanism that removes their heavy lesions, including pyrimidine dimers and nucleotides . Endonucleases are responsible for the lesion of the damaged strand.
c. Nucleotide excision repair is initiated by the proteins namely UvrA, UvrC, and UvrB in Escherichia coli.
-UvrD (helicase II) later removes the damaged strand
-DNA polymerase I (PolI) fills in the resulting gap.
d. DNA glycolases removes the damaged nitrogenous base.
-It leaves the sugar-phosphate backbone intact and thus creating an apurinic/apyrimidinic site, which is commonly referred to as an AP site.
e. Xeroderma pigmentosum complementation group A(XPA)
-This is an essential protein in the nucleotide excision repair pathway.
- It helps to make a pre-incision complex along with other proteins.
A. is your correct answer
The answer for this one is A
First one is geosphere
second is biosphere
third is atmosphere
Answer:
10 m/s/s or m/s²
Explanation:
Acceleration can be calculated by using the formula;
a = v - u/t
Where;
a = acceleration (m/s²)
v = final velocity (m/s)
u = initial velocity (m/s)
t = time (s)
In other terms, acceleration (a) can be represented as ∆V/t.
According to this question, a ball accelerates from 10 m/s (u) to 30 m/s (v) in 2 seconds. Hence, the acceleration of the ball is as follows:
a = 30 - 10/2
a = 20/2
a = 10m/s².
