Answer: The correct line is

Step-by-step explanation: We are given the following two sets of quadratic expressions in various forms:

We are to select one of the lines from above that represent three equivalent expressions.
We can see that there are three different forms of a quadratic expression in each of the lines:
First one is the simplified form, second is the factorised form and third one is the vertex form.
So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.
We have

and

So,

Thus, Line 1 contains three equivalent expressions.
Now,

and

So,

Thus, Line 2 does not contain three equivalent expressions.
Hence, Line 1 is correct.
I think the answer may be no solution
Answer:
<u>49</u> <em>is the best answer. Hope this helps!</em>
Step-by-step explanation:
Step-by-step explanation:
Hey there!
Firstly we need to find an equation of the line passing through point (-2,-2).
Now,
The equation of a st.line passing through point (-2,-2) is,

Now, putting the values,

It is first equation.
Now, another equation is,
y= 2x+3
Comparing, the equation with y = mx+c.
slope (m2)= 2
As per the condition of parallel lines,
m1=m2= 2
Putting, the values of m1 in equation (i)
(y+2)= 2(x+2)
y= 2x+2....is the equation.
Therefore, Jill's equation is correct answer.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>