Hello!
To find the line that is perpendicular to y = 3x - 2 and passes through the ordered pair (6, 8), we will:
- Find the negative reciprocal using the slope of the given function
- Substitute the given ordered pair into the new equation with the slope found in step 1
Let's remind ourselves of slope-intercept formula. Slope-intercept formula is y = mx + b, where m is the slope, and b is the y-intercept.
In the given equation, we know that 3 is slope. With that, we can find the negative reciprocal of that slope, and continue to step #2.
To find the reciprocal, we will need to flip our fraction. In this case, 3/1 = 3, so once we flip it, it is 1/3. Since it is the negative reciprocal, the fraction is a negative, so the negative reciprocal is -1/3.
Now, we will substitute the ordered pair into the slope-intercept formula with our new slope.
y = -1/3x + b (6, 8)
8 = -1/3(6) + b
8 = -2 + b (add 2 to both sides)
10 = b
Therefore, the equation of the line is y = -1/3x + 10.
There are 13 angles.
We know that
and
(11 angles)
1.
(9 angles)
2.
(8 angles)
3.
(7 angles)
4.
(6 angles)
5.
(5 angles)
6.
(4 angles)
7.
so we have a parallelogram.
(3 angles)
(2 angles)
8.
(1 angle)
9.
135/3= 45
Equation: 45w=s
45(8)= 360
Jeremiah saved $360.
Hope this helps!
