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lana66690 [7]
3 years ago
14

What is 13.62 divided by -3.14?

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

-4.3375796178343949044585987261146‬

Step-by-step explanation:

you can probably round it off but that is what my calculator gave me.

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-2(3h-1)=5(2h-3) has how many solutions are there
GREYUIT [131]

Answer:

1 solution

Step-by-step explanation:

-2(3h - 1) =5(2h - 3)

-6h + 2 = 10h - 15

-16h = -17

h = 17/16

Answer: 1 solution

8 0
3 years ago
Two card decks are drawn from a standard 52-card deck, without replacement. Find the probability that they are both aces.
LenaWriter [7]
I'm sorry, when I answered this I'm pretty sure I wasn't in algebra two yet. The correct answer is 4/52 * 3/51 = 1/221
6 0
3 years ago
Read 2 more answers
manuel has $15 to spend.on apps and music. Apps cost $2 each and songs cost $1 each. If x represents the number of apps purchase
strojnjashka [21]

Answer:

2x + y = 15

Step-by-step explanation:

Total amount with Manuel = $15

Cost of apps = $2

Cost of song = $1

x = number of apps purchased

y = number of songs purchased

Cost of apps × number of apps purchased + Cost of song × number of songs purchased = Total amount with Manuel

2*x + 1*y = 15

2x + y = 15

The linear equation that represents the combination of apps and songs manuel can purchase is 2x + y = 15

6 0
3 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
Find the measure of &lt; 1. <br> m &lt; 1 = degrees
Furkat [3]
<1 = 120/2 = 60

answer
60 <span>degrees</span>
8 0
3 years ago
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