There are 9 students in a class: 7 boys and 2 girls.

Mathematics

2 answers:

Lilit [14]3 years ago

5 0

I think the teacher would probably pick two boys and one girl

Mrrafil [7]3 years ago

3 0

Answer:

Step-by-step explanation:

There are 9C3 total ways of picking 3 people from 9 where order does not matter.

To pick 3 boys from 6, you must do 6C3

When you do both of these you divide the smaller by the larger.

9C3 = 84

6C3 = 20

So the probability that you want is

20/84 = 0.238

If you are uncertain where the 84 comes from, it is calculated like this

9*8*7*6! The 6!s cancel out and you are left with

=======

6! * (9 -6)!

9C3 = 9*8*7/3!

9C3 = 3 * 4 * 7 = 84

6C3 is done exactly the same way.

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Evaluate f(x)=7x+7 when x=-9

stealth61 [152]

Answer:

-56

Step-by-step explanation:

f(x) = 7x + 7

x = -9

We meed to plug in x = -9 into the first equation:

f(-9) = 7(-9) + 7

We can open up the parentheses:

f(-9) = -63 + 7

And then simplify:

f(-9) = -56

7 0

3 years ago

H function is even, odd, or neither. b. g(x) = x² - 2 Is it odd or even

o-na [289]

$g(x) = x^2 - 2 \text{ is even function }$

Solution:

Given that,

$g(x) = x^2 - 2$

We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

$\mathrm{Even\:Function:\:\:A\:function\:is\:even\:if\:}f\left(-x\right)=f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}\\\\\mathrm{Odd\:Function:\:\:A\:function\:is\:odd\:if\:}f\left(-x\right)=-f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}$