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4 years ago

14

Money off coupons has been circulated to 300 house holds.only 2/5m of these were redeemed (used) in the local supermarket to get

a free shampoo.what fraction of the coupons were unused?

1 answer:

Crank4 years ago

8 0

3/5 of 300 is 180. 180 coupons were unused.

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1. Find the measure of arc ABC<br><br> WILL GOVE BRAINLESTT

goblinko [34]

Answer:

180? I don't know it is correct

7 0

3 years ago

The diagram below models the layout at a carnival where G, R, P, C, B, and E are various locations on the grounds. GRPC is a par

mylen [45]

Answer:

The similar triangles are $\triangle BPE$ and $\triangle BCG$

$BE = 321$ and $PE =286$

Step-by-step explanation:

Given

See attachment for the required figure

Solving (a): The similar triangles

The similar triangles are $\triangle BPE$ and $\triangle BCG$

Solving (b): Why they are similar

Both triangles are similar because $\triangle BCG$ is dilated (i.e. enlarged) and then reflected to give $\triangle BPE$ .

Solving (c): Calculate BE and PE

The following are equivalent ratios

$BP: BC = BE : BG$

and

$BP: BC = PE : CG$

Solving for BE, we have:

$BP: BC = BE : BG$

Substitute the known values

$250:350 = BE:450$

Express as fraction

$\frac{250}{350} = \frac{BE}{450}$

Multiply both sides by 450

$450 * \frac{250}{350} = BE$

$321 = BE$

$BE = 321$ -- approximated

Solving for PE, we have:

$BP: BC = PE : CG$

Substitute known values

$250:350 = PE:400$

Express as fraction

$\frac{250}{350} = \frac{PE}{400}$

Multiply both sides by 400

$400 * \frac{250}{350} = PE$

$286 = PE$

$PE =286$

5 0

3 years ago

What decimal is equivalent to each fraction?

Maksim231197 [3]

1/6 = 0.16 with a line over the 6 because it is repeating

3 0

3 years ago

To derive the standard formula of a circle, a radius r is constructed as the hypotenuse of a right triangle as shown. On a coord

vlabodo [156]

Answer:

The answer is "x-h and y-k".

Step-by-step explanation:

The center is (h, k) with E (x, y) point, and its length of the legs used during extracting the standard circle equation should be found. Its right triangle length base is (x-h) units, as well as the right triangle's length, is (y-k). So, these are the required leg lengths, that's why the above-given points are correct.

4 0

3 years ago

Draw a quadratic function below with zeros at -3 and 5 that is also concave up.

tia_tia [17]

Hello from MrBillDoesMath!

Answer:

x^2 - 2 x - 15

Discussion:

( x - (-3)) * ( x- 5) =

(x +3) (x-5) =

x^2 - 2 x - 15

It is a concave upward curve (looks like a "u") as the x^2 term causes the function to grow larger as x approaches +\- infinity.

Thank you,

MrB

8 0

4 years ago