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Goshia [24]
3 years ago
13

Please help me ASAP!!! Thank you!!

Mathematics
1 answer:
Airida [17]3 years ago
5 0

Answer:

Y≤-3/4x+2

Step-by-step explanation:

less than because the bottom of the line is shaded

equal to because the line is solid

slope you go down three and go right four which is negative

y intercept is where x=0

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HELP MEE :)) PLEASEEE <3
Mandarinka [93]
<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = 3.14 \times  {2}^{2}  \times 3

v = 37.68 \:  {cm}^{3}

<h3>Volume of the rectangular prism:</h3>

v = lwh

v = 6 \times 5 \times 7

v = 210 \:  {cm}^{3}

<h3>Total volume:</h3>

v = 37.68 + 210

v = 247.68 \:  {cm}^{3}

4 0
1 year ago
Read 2 more answers
Which is the mode of this data?<br><br> 12, 19, 22, 17, 15, 18, 15, 14, 16
Snezhnost [94]
Answer: 15
REMEMBER: The mode is the value that appears most frequently in a data set.
4 0
2 years ago
Find the equation for the line that passes through (4, - 8) that has slope - 2. Give your answer in
NNADVOKAT [17]

Answer:

y+8=-2(x-4)

Step-by-step explanation:

point-slope form is y-y1=m(x-x1) where m is the slope, and (x1,y1) is a point.

We are given all of that information:

slope: -2

point: (4,-8)

substitute the numbers into the equation

y--8=-2(x-4)

we can make --8 to positive 8

so:

y+8=-2(x-4)

this is the equation in point-slope form

Hope this helps!

4 0
2 years ago
What is the positive solution to the equation 0 = –x2 + 2x + 1? Quadratic formula: x = StartFraction negative b plus or minus St
Vladimir [108]

Answer:

See attached for a "Neat" quadratic formula.

a = -1

b = 2

c = 1

x = [-2 +- sqr root( 4 -4*-1*1)] / -2

x = [-2 +- sqr root( 4 -4*-1*1)] / -2

x = [-2 +- sqr root(8)] / -2

x1 = (-2 +2.8284271247)  / -2

x1 = .8284271247 / -2

x1 = -0.41421

x2 = (-2 -2.8284271247)  / -2

x2 = ( -4.8284271247)  / -2

x2 = 2.4142135624

So the equation has the positive solution of

2.4142135624

Step-by-step explanation:

3 0
2 years ago
(NEED HELP! WILL RATE 5 STARS!)
vitfil [10]

Answer:I think it's 1/61

Step-by-step explanation:If I am correct plz don't forget to thank me...

3 0
2 years ago
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