The answer to this question is False
Answer:
:, Segment subtended by the same angle on two adjacent parallel lines are congruent
Step-by-step explanation:
Statement, Reason
MNOP is a parallelogram:, Given
:, Opposite sides of a parallelogram
∠PMO ≅ ∠MON:, Alternate Int. ∠s Thm.
:, Opposite sides of a parallelogram
∠POM ≅ ∠NMO:, Alternate Int. ∠s Thm.
OM ≅ OM:, Reflexive property
:, Segment subtended by the same angle and on two adjacent parallel lines are congruent
Answer:
810
Step-by-step explanation:
450 × 1.80 = 810
The 1 represents how there is no markdown and the .80 is the 80% being marked up.
I think there is a more specific equation for this than the one I showed, but this was my way of solving these questions without giving myself a headache
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
3wx/6x * 3wx/9w = w/2 • x/3 = xw/6
Answer: xw/6