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HACTEHA [7]
4 years ago
12

What is the center of the circle given by the

Mathematics
1 answer:
Andru [333]4 years ago
5 0

Answer:

B. (−17, 4)

Step-by-step explanation:

We can write the equation of a circle in the form

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x + 17)^2 + (y − 4)^2 = 23

(x - -17)^2 + (y − 4)^2 = ( sqrt (23))^2

The center is (-17,4) and the radius is (sqrt(23)

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\large\underline{\sf{Solution-}}

\textsf{Given expression;}\\

\rm{23 =  \frac{7}{9}(6x - 36) + 9 } \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256)}{9}  + 9 \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 256 + 81)}{9}  \\

\rm{\longmapsto} \: 23 =  \frac{(42x - 175)}{9}  \\

\rm{\longmapsto} \:  \frac{23}{1}  =  \frac{(42x - 175)}{9}  \\

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\rm{\longmapsto}23(9) = 1(42x - 175) \\

\rm{\longmapsto}207 =42x - 175\\

\rm{\longmapsto} \: 42x =  - 175 - 207 \\

\rm{\longmapsto} \: 42x =  - 379 \\

\rm \therefore \: x =  -  \frac{375}{42}  \\

\textsf{Hence, the value of x will be -375/42 respectively.}\\

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