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Alika [10]
3 years ago
12

What is the algebraic expression that describes the monthly salary? Let x be the hours of training.

Mathematics
2 answers:
anygoal [31]3 years ago
3 0
I believe it is A i just tried


zhuklara [117]3 years ago
3 0
It's A, I just took a quiz on that and that's the answer
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Help Please I'm Out Of Time ;(
Dafna11 [192]

Answer:

Not true.

Step-by-step explanation:

Whole numbers are integers that are 0 or greater than 0.  Since 0 is a whole number and x > 0 does not include 0, the statement is not true. Only the sign ≥ includes 0.

6 0
3 years ago
Say that the economy is in a recession, causing vehicle prices to drop by eight percent. If your car was previously worth $25,29
qaws [65]

Answer:

c.

$23,271

Step-by-step explanation:

i took the same test on edg

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2 years ago
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a restaurant used 9.6 ounces of cheese to make 6 slices of pizza. if each slice had the same amount of cheese, how much cheese w
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8 0
3 years ago
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
How do I solve 300x300=
UNO [17]

Answer:

its 90,000

Step-by-step explanation:

just put the zeros together then multiply 3x3

5 0
3 years ago
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