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3 years ago

What is the algebraic expression that describes the monthly salary? Let x be the hours of training.

Mathematics

2 answers:

anygoal [31]3 years ago

3 0

I believe it is A i just tried

zhuklara [117]3 years ago

3 0

It's A, I just took a quiz on that and that's the answer

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Please help...........

Alla [95]

Mel took 8 more strokes b/c

-6+6=0

0+3=3

6+3=8 or

-6+8=3

7 0

4 years ago

A box contains

GarryVolchara [31]

The first one is 7/10 and the second one is 5/10

5 0

3 years ago

Read 2 more answers

Given α and β are Supplementary. Show the necessary steps.

user100 [1]

Answer:

$\alpha = 108\degree, \: \beta = 72\degree$

Step-by-step explanation:

α and β are Supplementary (given)

$\therefore \alpha + \beta = 180\degree.... (1)$

It is given that:

$\alpha= \frac{3}{2} \beta$

Plugging the value of α in equation (1), we find:

$\frac{3}{2} \beta + \beta = 180\degree$

$\therefore \frac{3+2}{2} \beta = 180\degree$

$\therefore \frac{5}{2} \beta = 180\degree$

$\therefore \beta = 180\degree\times \frac{2}{5}$

$\therefore \beta = 72\degree$

$\implies \alpha= \frac{3}{2} \times 72\degree= 108\degree$

So,

$\alpha = 108\degree, \: \beta = 72\degree$

7 0

3 years ago

Need help with this ASAP. Thanks

ioda

Answer: check explanation

Step-by-step explanation:

Multiply both sides of equation by x(x+a)

This will get rid of those nasty fractions...cuz who likes them?

Anyways,

Now you should I think get

x(x+a)+a(ax)=a

I am pretty positive that you just distribute and solve.

You may have to factor and have to put everything as an equation set to equal=0

you try it and experiment. Sometimes you just have to try to think algebraically and creatively. Don’t get frustrated just work with it. Good luck!

5 0

3 years ago

f r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Leya [2.2K]

The equivalent expression to $\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}$

<h3>What are the equivalent expressions?</h3>

Equivalent expressions are similar expressions that may have different forms but when a value is replaced with the variables in the same form provides the same answer.

From the information given, If:

r(x) = 3x - 1
s(x) = 2x + 1

Then the fractional form can be an expression as:

$\mathbf{(\dfrac{r}{s})(x)= \dfrac{3x-1}{2x+1}}$

where;

x = 6

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{3(6)-1}{2(6)+1}}$

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{18-1}{12+1}}$

$\mathbf{(\dfrac{r}{s})(6)= \dfrac{17}{13}}$

Learn more about equivalent expressions here:

brainly.com/question/24734894

#SPJ1

8 0

2 years ago