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cupoosta [38]
3 years ago
14

Number of Text Messages a Day A random sample of n = 755 US cell phone users age 18 and older in May 2011 found that the average

number of text messages sent or received per day is 41.5 messages,32 with standard error about 6.1. State the population and parameter of interest. Use the information from the sample to give the best estimate of the population parameter. Find and interpret a 95% confidence interval for the mean number of text messages.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

The 95% confidence interval is  (29.54 - 53.46}

Step-by-step explanation:

given data:

\hat X = 41.5

Se = 6.1

n = 755

a) best estimate  \hat x = 41.5

b) at 95% confidence interval

\alpha = 1- 0.95 = 0.05

\alpha /2 = 0.025

z_{\alpha/2} = z_{0.025} = 1.96

at 95% confidence interval for [/tex]\mu[/tex]

\hat x \pm z_{\alpha /2} \times Se

41.5 \pm 1.96\times 6.1

41.5 \pm 11.96

The 95% confidence interval is  (29.54 - 53.46}

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Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol
Zigmanuir [339]

Answer:

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Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.      

We will use volume formula of sphere to solve our given problem.

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The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3

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\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3

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Find the value of x for the right triangle. Round your answer to the nearest hundredth
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tan35=opposite ➗ adjacent

0.7002=27 ➗ x

Cross multiplying we get

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Divide both sides by 0.7002

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x=38.56041131

x=38.56 nearest hundredth

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