Given:
257J of heat
5500g of mercury
increase by 5.5
degrees Celsius
Required:
Specific heat of
mercury
Solution:
H
= mCpT
257J = (5500g of
mercury) Cp (5.5 degrees Celsius)
Cp = 8.5 x 10^-3
Joules per gram per degree Celsius
Answer:
both the substances will evaporate
Explanation:
I am not to sure because I have not studied this
Answer:
Explanation:
first to get the density of some thing you have to devide the mass by the volume so 0.00018 (divided) by 10 kg and that gives you ur answer