Answer:
1.D) CH4 + 2O2 → CO2 + 2H2O
2C)2,1,2
3.D)SIO2 + 4HF → SIF4 + 2H2O
4.D)2As + 6NaOH → 2Na3AsO3 + 3H2
5.C)SiCI4 + 2H2O → SiO2 + 4HCI
Explanation:
equal number of atoms of each elements in both the sides of the chemical equation is required to have an equation in balanced state.
N=24/12
n=2
where n= no. of moles
The combustion of ammonia in presence of excess oxygen yields NO2 and H2O.
The molar mass of ammonia is 17.02 g/mol
Therefore, moles of ammonia in 43.9 g
= 43.9 /17.02
= 2.579 moles
From the equation the mole ratio of ammonia to nitrogen iv oxide is 4:4
The molar mass of NO2 is 46 g/mol
The number of moles of NO2 is the same as that of ammonia since they have equal ratio,
= 2.579 moles
Therefore, mass of NO2
= 2.579 moles ×46
= 118.634 g
≈ 119 g
