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4 years ago

Find the area of the region under y=e^x and above y=1 for 0 less than equal to x less than equal to 5.

1 answer:

6 0

$\int\limits_{0}^{5}(e^x-1)dx=\int\limits_{0}^{5}e^xdx-\int\limits_{0}^{5}1dx=e^x|^5_0-x|_0^5=e^5-e^0-(5-0)=
\\
\\=e^5-1-5=e^5-6$

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The sum of 86, 68, and 38 is 192. What else do you know about the sum of 68, 38, and 86?

Sveta_85 [38]

We have 2 given numbers:
=> 86 + 68 + 38 = 192
=> 68 + 38 + 86 = 192 also
This kind of process used commutative property system of equation in where:
a + b = b + a
No matter what sequence you are going to use, the answer would always be the same.
In the given 2 equations, notice that both digits of 2 group of equation contains the same number. The only difference is they were added with different orders. Yet the answers are still the same.

8 0

3 years ago

Elaine found the following in her pocket. How much money was in her pocket

jenyasd209 [6]

Answer:

we need the numbers... or like the coins, or something to solve it with. you need to include what was actually in here pocket lol

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2 years ago

after every eighth visit to a restaurant you receive a free beverage.after every tenth visit you receive a free appetizer. if yo

Alik [6]

On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.

8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.

Thus making 40 and 80 the answers. I hope this helps!

3 0

3 years ago

Which statement correctly describes the expression

pav-90 [236]

Answer:

Step-by-step explanation:

choice A means

$11 - 2 {m}^{3}$

choice B means

$2m - 11$

choice C means which is the answer

${2m}^{3} - 11$

choice D means

${(2m)}^{3} - 11$

hope it helps ❤❤❤

For any question comment me

3 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago