Question

Find the area of the region under y=e^x and above y=1 for 0 less than equal to x less than equal to 5.

Answer 1

$\int\limits_{0}^{5}(e^x-1)dx=\int\limits_{0}^{5}e^xdx-\int\limits_{0}^{5}1dx=e^x|^5_0-x|_0^5=e^5-e^0-(5-0)= \\ \\=e^5-1-5=e^5-6$