Answer:
C' (4, - 6 )
Step-by-step explanation:
4 units left means subtracting 4 from the x- coordinate
3 units down means subtracting 3 from the y- coordinate
C (8, - 3 ) → C' (8 - 4, - 3 - 3 ) → C' (4, - 6 )
Answer:
Therefore,
The area of the sector is 15.09 unit².
Step-by-step explanation:
Given:
Circle with,
radius = r = 6 unit
central angle = θ = 48°
pi = 3.143
To Find:
Area of sector = ?
Solution:
If 'θ' is in degree the area of sector is given as

Substituting the values we get

rounded to nearest hundredth
Therefore,
The area of the sector is 15.09 unit².
RemarkIf you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step OneDivide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step TwoDifferentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =

Frankly I like the first answer better, but you have a choice of both.
Answer:
C) y=3
Step-by-step explanation:
4y squared - 7y = 15
4(3) squared -7(3)=15
4(9) -7(3)=15
39-21=15
15=15
3÷?=36
multiply both sides by 3 to figure out what "?" is
36*3=108
3÷108=36
?=108