<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
see below
Step-by-step explanation:
This graphs as 3 horizontal lines. The open circles are at the ends of the interval where the function is undefined or is defined as a different value.
Answer:
Organisms that break down dead or decaying organisms
Step-by-step explanation:
Hope this helps :b