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3 years ago

What is the product (-6a^3b+2ab^2

Mathematics

1 answer:

Irina-Kira [14]3 years ago

4 0

you have to apply this formula (a+b)(c-d)=ac-ad+bc-bd

-6a^3*b*5a^2+6a^3b*2ab+6a^3b*b+2ab^2*5a^2-2ab^2*2ab-2ab^2*b=

-30a^5*b+12a^4b^2+6a^3b^2+10a^3b^2-4a^2b^3-2ab^3

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3 years ago

Read 2 more answers

Determine the lengths of the sides of the rectangle using the given area. Give answers both exactly and

Degger [83]

Answer:

Part a) Exactly values

The width of the rectangle is $\frac{\sqrt{70}}{2}\ cm$

The length of the rectangle is $2\sqrt{70}\ cm$

Part b) Approximately values

The width of the rectangle is $4.2\ cm$

The length of the rectangle is $16.7\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

$A=LW$

we have

$L=4x\ cm\\W=x\ cm$

substitute the values in the formula

$A=4x(x)$

$A=4x^2$

$A=70\ cm^2$

$70=4x^2$

Solve for x

Divide by 4 both sides

$\frac{70}{4}=x^2$

square root both sides

$x=(+/-)\frac{\sqrt{70}}{2}$

The solution is the positive value

$x=\frac{\sqrt{70}}{2}$

therefore

<em>Exactly values</em>

$L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm$

<em>Approximately values</em>

$L=4\sqrt{70}}{2}=16.7\ cm\\\\W=\frac{\sqrt{70}}{2}=4.2\ cm$

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3 years ago

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3 years ago

A and B are independent events. If P(A) = 0.50 and P(A and B) = 0.20, find P(B).

rewona [7]

The independent events are illustrations of probability, and the value of P(B) is 0.40

<h3>How to determine the value of P(B)?</h3>

The given parameters are:

P(A) = 0.50

P(A and B) = 0.20

Two events A and B are independent, if

P(A and B) = P(A) * P(B)

So, we have:

0.50 * P(B) = 0.20

Divide both sides by 0.50

P(B) = 0.40

Hence, the value of P(B) is 0.40