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Nastasia [14]
3 years ago
5

5 customers buy 10,15,20,25,30 toffees respectively from 1 shop. But the the person who bought 20 toffees forgot to pay .if the

shopkeeper makes 20% profit what will be his profit or loss from these five customers of the person who forgot to pay at pay his amount had paid his amount?
50% profit ,60% profit, 40% loss ,20% loss.
Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

40% profit

Step by step Explanation:

Profit percentage

=( profit/cost price) * 100

0.2 = profit/cost

10+15+20+25+30= 100

Let's assume the cost price of the items is $1 each

Cost price total= $100

Profit made when buyer of 20 toffe didn't say was

0.2=profit/cost

0.2*100 =$20

If the$ 20 paid.

Total profit = $40

So percentage profit now

40/100 * 100 = 40%

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Studentka2010 [4]

Answer:

I need the length, width, and height

Step-by-step explanation:

3 0
3 years ago
How do I find the vertex and the standard form? Plz explain
xenn [34]

Answer:

Vertex form

y = -4(x + 3)^2 + 10

Standard form;

y = -4x^2-24x - 26

Step-by-step explanation:

Mathematically, we have the vertex form as

y = a(x-h)^2 + k

(h,k) represents the vertex

We have h as -3 and k as 10

y = a(x+3)^2 + 10

To get a, we substitute any of the points

Let us use (-1,-6)

-6 = a(-1+3)^2 + 10

-6-10 = 4a

4a = -16

a = -16/4

a = -4

So we have the equation as;

y = -4(x+3)^2 + 10

For the standard form;

We expand the vertex form;

y = -4(x + 3)(x + 3) + 10

y = -4(x^2 + 6x + 9) + 10

y = -4x^2 - 24x -36 + 10

y = -4x^2 -24x -26

7 0
2 years ago
F(x) = 5х – 3<br> f(5) =
Sophie [7]

Answer:

f(5)=22

Step-by-step explanation:

since x=5 substitute 5 with x

f(5)=5(5)-3

multiply

f(5)=25-3

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4 0
2 years ago
Read 2 more answers
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
If y = 8 cm, what is the area of the blue section of this shape?
Ivahew [28]

Answer:

56 cm squared

Step-by-step explanation:

First things first: Cop one triangle off the rectangle, and attach it to the other one, so the shape looks like a L

Now I can actually solve this:

The left side is 8 cm (because y = 8 cm)

The top is 10 cm

The middle is 6 cm

The inside left is 3 cm

And the very bottom is 2 cm

First, we'll solve for the newly constructed rectangle: 3 x 2. That equals 6.

Next, solve for the longer rectangle: 10 x 5. That's 50.

Now, add the two areas, and we get 56. So the area of the whole thing is 56 cm squared.

(Please keep in mind that I could be wrong, so double check it for me, thanks!)

7 0
2 years ago
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