What is the slope of the equation?<br><br> y = -1/3x + 3

Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below.

Kisachek [45]

Answer: No the students work is not correct. Because you are using distribution. Which means that 3 has to multiply the y2 and 2 not just the y2! And after you distribute it you need to simplify!

Step-by-step explanation:

6 0

2 years ago

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$4750 invested at 10% p.a compounded semiannually for 10 years, calculate the interest

alexgriva [62]

<h3>Answer: $7,853.16</h3>

Work Shown:

A = P*(1+r/n)^(n*t)

A = 4750*(1+0.10/2)^(2*10)

A = 12,603.164099436

A = 12,603.16

That represents the account balance after 10 years. To find the interest only, subtract off the deposit amount.

interest = A-P = 12,603.16 - 4,750 = 7,853.16

6 0

2 years ago

Select all the correct answers.

ValentinkaMS [17]

Answer:

ideas and conflict and maybe elements depending on the story

3 0

2 years ago

An automobile manufacturer has given its van a 31.3 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Fynjy0 [20]

Answer:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

Step-by-step explanation:

Information given

$\bar X=31.1$ represent the sample mean

$\sigma=1.3$ represent the population standard deviation

$n=140$ sample size

$\mu_o =31.3$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is equal to 31.3 MPG, the system of hypothesis would be:

Null hypothesis: $\mu =31.3$

Alternative hypothesis: $\mu \neq 31.3$

Since we know the population deviation, the statistic is given by

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing we got:

$z=\frac{31.1-31.3}{\frac{1.3}{\sqrt{140}}}=-1.82$

The p value for this case would be given by:

$p_v =2*P(z$

For this case since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 31.3 MPG

4 0

3 years ago

Convert –18° to radians. Negative 10 pi radians Negative StartFraction 10 Over pi EndFraction radians Negative StartFraction 1 O

REY [17]

Answer:

negative pie/10 radians

Step-by-step explanation:

d on edg

6 0

2 years ago

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What is the slope of the equation? y = -1/3x + 3