Answer:
Total number of pages in the book is 234.
Step-by-step explanation:
Let us assume that the total number of pages in the book = <em>x</em>
Now, it is given that Makaila read 44 pages yesterday.
Also, Makaila read two-third of the book today. As we have assumed that, there are a total of x number of pages in the book, so we can say that Makaila read two-third of <em>x </em>number of pages today.
Number of pages read by Makaila today = 
Now, it is also given that, Makaila read a total of 200 pages in the past two days.
∴ according to question,
Pages read yesterday + Pages read today = 200
⇒
⇒
⇒
⇒![132+2x=200\times3\;\;\;\;\;\;\;\;\;[On\;cross-multiplying]](https://tex.z-dn.net/?f=132%2B2x%3D200%5Ctimes3%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5BOn%5C%3Bcross-multiplying%5D)
⇒
⇒
⇒
⇒
∴ Total number of pages in the book = <em>x</em> = 234
The answer is B multiplication That’s correct who is the
Answer:
n(AUB)=n(A)+n(B)–n(AnB)
n(AUB)=n⁰(A)+n⁰(B)+n(AnB)
Step-by-step explanation:
This is the formula i have learned. Hope this will help u. U can use them according the question type.
Answer:
An equation parallel to 4x + 5y = 19 would be y = -4/5x +12.
An equation perpendicular to 4x + 5y = 19 would be y = 5/4x + 10.
Step-by-step explanation:
The equation given represents a linear equation in Standard Form (Ax + By = C). Lines that are parallel to each other go the same direction and don't touch, so their slopes must be the same. However, lines that are perpendicular go in opposite directions and intersect, so their slopes must be the direct opposite of each other. In order to find the slope, you must first convert from the Standard Form given to Slope Intercept Form (y = mx +b). When you solve the given equation for 'y', you get: y = -4/5x + 19, where the slope = -4/5. To make a parallel equation, simply keep the same slope and choose a different y-intercept ('b'). To make a perpendicular equation, take the direct opposide of your slope 5/4 (positive) and choose a different y-intercept.
3/4 = 0.75 in decimal inch
Karla wants to leave 0.75 inch in her signature.
4 -0.75 = 3.25 inch needed
0.25 = 1/4
3 and 1/4 inches is needed.