Nolan and his children bought fruits (Apples and bananas) worth $8.
Cost of each apple and bananas are $2 and $0.40 respectively.
Let the number of bananas he bought = y
And the number of apples = x
Therefore, cost of the apples =$2x
And the cost of bananas = $0.40y
Total cost of 'x' apples and 'y' bananas = $(2x + 0.40y)
Equation representing the total cost of fruits will be,
(2x + 0.40y) = 8
10(2x + 0.40y) = 10(8)
20x + 4y = 80
5x + y = 20 --------(1)
If he bought 5 times as many bananas as apples,
y = 5x ------(2)
Substitute the value of y from equation (2) to equation (1),
5x + 5x = 20
10x = 20
x = 2
Substitute the value of 'x' in equation (2)
y = 5(2)
y = 10
Therefore, Nolan bought 2 apples and 10 bananas.
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2. Using the external angle of a triangle theorem.
6x - 17 = 3x - 11 + 2x + 11
6x - 5x = 17
x = 17
So m angle K = 2(17) + 11
= 45 degrees answer
3. The diagonals are both medians of the triangle so the 2 parts are in the ratio 2:1 so 3:x = 2:1 and x = 1.5 answer
2:1
The mean is 26 and the MAD is 3.75
If the remaining 4 letters can be anything, you have 2*26^4 = 913,952 possible 5-letter ham radio call signs.
Answer:
9/29
Step-by-step explanation:
There are 29 students. 11 don't play a sport, so there are 18 students who play a sport.
The number of students who play both sports is:
18 = 13 + 14 − x
x = 9
So the probability is 9/29.
