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3 years ago

I found a place that would give me a 20% discount if spend over $50. My bill is $75. what is my final bill after the savings

Mathematics

1 answer:

luda_lava [24]3 years ago

4 0

60 dollars 60 Dollars 60 Dollars sixty dollars sixty dollars sixty dollars
75x.2 or 20% equal 15. 75-15=60

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Factor ab + 2a + 3b + 6

EastWind [94]

The answer is (b+2)(a+3)

You have to group each like term but have them be able to separate evenly so when you do the foil method it goes back to the original equation.

7 0

3 years ago

Read 2 more answers

Mohammad divide Rs 82000 into two parts such that the amounts at 5% per annum compound interest in 2 years and 3 years are equal

lara [203]

Answer:

Rs 42000 and Rs 40000

Step-by-step explanation:

Given that Rs 82000 is divided into two parts.

Let the first part be Rs x which is compounded annually at the interest of 5% per annum for 2 years.

The rate of interest = 5%=0.05

The total amount after 2 years $= x(1+0.05)^{2}\cdots(i)$

The other part is Rs 82000-x which is compounded annually at the interest of 5% per annum for 3 years.

The total amount after 3 years $= (82000-x)(1+0.05)^{3}\cdots(ii)$

As both the amounts are equal, so from equation (i) and (ii)

$x(1+0.05)^{2}=(82000-x)(1+0.05)^{3} \\\\x(1.05)^{2}=82000(1.05)^{3} -x(1.05)^{3} \\\\x(1.05^2+1.05^3)=82000\times 1.05^3 \\\\x(2.260125)=94925.25 \\\\x=94925.25/2.260125 \\\\$

x= 42000

And the other part = 82000-42000 = Rs 40000

Hence, he divides the money as

Rs 42000 at 5% per annum compound interest in 2 years and

Rs 40000 at 5% per annum compound interest in 3 years.

4 0

2 years ago

Maddie has a retangular garden in her backyard. The perimeter of the garden is eighty-two feet. The width is five shorter than t

Ulleksa [173]

The length is 46 feet and the width is 36 feet.

5 0

2 years ago

Find the missing term (x^12)^5 x (x^-2)^9 x what =(x^40)^5

Annette [7]

Answer:

$x^{158}$

Step-by-step explanation:

We are given,

$(x^{12} )^{5} \times (x^{-2} )^{9} \times y = (x^{40} )^{5}$ .

It is required to find the value of y.

Now, on simplifying above equation, we get,

$x^{60} \times x^{-18} \times y = x^{200}$

i.e. $x^{42} \times y = x^{200}$

i.e. $y = x^{200} \times x^{-42}$

i.e. $y = x^{158}$

Hence, the missing term is $x^{158}$ .

3 0

3 years ago

Read 2 more answers

Determine whether the statement is always true, sometimes true, or never true. Give an example. (a) Both sides of an equation ca

arsen [322]

Answer:

(A) Always true

(B) Seldom true

Step-by-step explanation:

(A) Both sides of an equation can be multiplied by the same number without this action changing the solution of the equation.

Keyword here is "number".

Multiplying both sides of an equation by an equal quantity (same number) will result in same solution after solving for the unknown in the equation. This is because that numeric quantity can always be removed by dividing both sides of the equation by it or by a factor (or multiple) of it.

EXAMPLE:

For a linear equation, 4x - 6 = 15x

let's find the solution, in other words solve for the unknown value X.

4x - 15x = 6

-11x = 6

x = -6/11

Now multiply both sides of the equation by 3.

3(4x - 6) = 3(15x)

12x - 18 = 45x ___new equation

Solve for X

12x - 45x = 18

-33x = 18

x = -18/33

Reduce the fraction to its simplest form by looking for a number that can divide both numerator and denominator without remainder. In other words, think of a number that is a factor of 18 and a factor of 33.

That common factor or highest common factor (HCF) is 3.

Go ahead and reduce the fraction.

x will be reduced to -6/11

(B) Both sides of an inequality can seldom be multiplied by the same number, without such action changing the solution set of the equation.

Inequalities are more complex. Operational signs even change sometimes, in the course of finding the solution set of the inequality.

Sometimes, multiplying both sides of an inequality by a given numeric quantity will change its solution set and sometimes, it won't.

5 0

3 years ago