Total number of 10 grader students = 260 students.
Total number of students who rides the bus and they are of 10th grader = 150 students.
Probability (a student rides the bus given that they are a 10th grader) =
Therefore,
P(E) = 
Dividing top and bottom by 10, we get
P(E) = 15/26.
In decimals 0.577.
Therrefore, correct option is C) 150/260 = 15/26 = .577.
Answer:
Step-by-step explanation:
|4x + 3| = 9 + 2x
We see the absolute value so we have to consider 2 cases:
(1)
4x + 3 = -9 - 2x
6x = -12
x = -2
(2)
4x + 3 = 9 + 2x
2x = 6
x = 3
Let's plug in both results.
|4(-2) + 3| = 9 + 2(-2)
|-5| = 9 - 4
5 = 5
Therefore x = -2 is a solution
|4(3) + 3| = 9 + 2(3)
|15| = 9 + 6
15 = 15
Therefore x = 3 is also a solution.
Answer:
So about 95 percent of the observations lie between 480 and 520.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
The mean is 500 and the standard deviation is 10.
About 95 percent of the observations lie between what two values?
From the Empirical Rule, this is from 500 - 2*10 = 480 to 500 + 2*10 = 520.
So about 95 percent of the observations lie between 480 and 520.
Answer:
10.439 Km
Step-by-step explanation:
If K is midpoint of JL then JK = 0.5JL
JL = 4x - 2; JK = 7
The equation:
0.5(4x - 2) = 7
2x - 1 = 7 |add 1 to both sides
2x = 8 |divide both sides by 2
<u>x = 4</u>
<u>JL</u> = 4(4) - 2 = 16 - 2 = <u>14</u>
<u>KL</u> = JK =<u> 7</u>
