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3 years ago

Find a cubic function with the given zeros.

1 answer:

6 0

An eqution with roots r1,r2,r3 is factored form as
(x-r1)(x-r2)(x-r3)

roots are √7, -√7, and -4

(x-√7)(x+√7)(x+4)
multiply
(x^2-7)(x+4)
x^3+4x^2-7x-28

2nd option si right naswer

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Help me find the area of the shaded region

dalvyx [7]

I think it’s 50 but idk

7 0

3 years ago

Maria receivesa commission of 11.5%for each pair of shoes she sells.She earned $207 in commission last week.What was the dollar

Kamila [148]

Answer:

$1800

Step-by-step explanation:

You would use proportions. 11.5/100 (11.5%) multiplied by 207/x.

Cross multiply 100 and 207, then divide that answer by 11.5. You should get 1,800 as your answer.

Therefore, the dollar amount of shoes that Maria sold is $1800.

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3 years ago

Simplify the following polynomial expression. A. B. C. D. <br> (5x^4-9x^3+7x-1)

jek_recluse [69]

Answer:

The answer to the expression (5x^4-9x^3+7x-1) = -98

Step-by-step explanation:

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3 years ago

What is the ratio of the volume of a cube with edge length six inches to the volume of a cube with edge length one foot? Express

gladu [14]

Answer:

The ratio is $\frac{1}{8}$

Step-by-step explanation:

The volume of a cube with edge length a is:

$V = a^{3}$

We have two cubes:

Cube 1: The one with edge length of six inches.

Cubs 2: The one with edge length of one foot.

The ratio is:

$R = \frac{V_{C1}}{V_{C2}}$

In which $V_{C1}$ is the volume of the first cube and $V_{C2}$ is the volume of the second cube.

Volume of the first cube

The edge length is 6 inches, so $a = 6$ .

$V_{C1} = 6^{3} = 216 inches^{3}$

Volume of the second cube

To express the ratio as a common fraction, both volumes must be in the same unit. So we must pass the edge length of the second cube to inches.

The second cube has edge length of one foot. Each foot has twelve inches. So

$V_{C2} = 12^{3} = 1720 inches^{3}$

Ratio:

$R = \frac{V_{C1}}{V_{C2}} = \frac{216}{1720} = \frac{1}{8}$

3 0

2 years ago

Roger wishes to determine the average high

mafiozo [28]

Roger's method would not provide relevant results for what he was trying to accomplish because he was calculating average over a 3 month period instead of for a single day.

<h3>How to find the mean temperature?</h3>

Mean/Average of any given data simply means the sum of the given data divided by the sample size of the given data.

Now, when talking about average temperature, it simply means adding the temperatures for the duration you intend to analyze and then dividing the sum by the number of temperatures you added.

However, in this question Roger wants to find the average temperature for any given data and we know the temperatures in a 24-hour day may differ from time to time and as such the mean/average for a particular day would simply be found by adding up temperatures for the day and then dividing by the number of temperatures added.

Thus, Roger's method would not provide relevant results for what he was trying to accomplish because he was calculating average over a 3 month period instead of for a single day.

Read more about Mean Temperature at; brainly.com/question/1456846

#SPJ1

8 0

1 year ago