All categories

2 years ago

Hans house is $450 meters from school. Lin’s house is 145 meters closer to school. How far is Lin’s house from school?

Mathematics

1 answer:

Yuki888 [10]2 years ago

7 0

Answer:

305 meters

Step-by-step explanation:

You just have to subtract Lin's house's distance from Han's house from Han's house's distance to school. ---

450-145

=305

305m

You might be interested in

In a survey 7/8 of the people surveyed said that recycling is important. Only 1/2 of them buy products made with recycled materi

morpeh [17]

Answer:

only 3.5 buy products made with recycled material but you have to round it to 4

5 0

3 years ago

I owe old is Mukesh ambani.

ololo11 [35]

Answer:yes

Mukesh is 61 years old.

3 0

3 years ago

Read 2 more answers

Find f^3(x) for f(x)=4/x^2

vaieri [72.5K]

Answer:

f³(x) = 64/x⁶

Step-by-step explanation:

f³(x) = (f(x))³ = (4/x²)³ = 4³/(x²)³

f³(x) = 64/x⁶

_____

The applicable rules of exponents are ...

(a/b)^c = (a^c)/(b^c)

(a^b)^c = a^(bc)

7 0

3 years ago

Which statements regarding the diagram Triangle EBC are true? Select three options

Fynjy0 [20]

Answer:

The answer would be:

B. ∠DEC is an exterior angle.

Step-by-step explanation: Your welcome

6 0

3 years ago

Read 2 more answers

Just help me plssssssssss

Komok [63]

Answer:

The perimeter of triangle is 30ft.

Step-by-step explanation:

First you have to find the value of a using Pythogoras Theorem, a² + b² = c² where a and b is the sides and c is the hypotenuse :

${a}^{2} + {b}^{2} = {c}^{2}$

${a}^{2} = {c}^{2} - {b}^{2}$

$a = \sqrt{ {c}^{2} - {b}^{2} }$

Let b = 12,

Let c = 13,

$a = \sqrt{ {13}^{2} - 12 {?}^{2} }$

$a = \sqrt{25}$

$a = 5feet$

Next you have to find the perimeter of triangle by adding all the sides together :

$perimeter = 5 + 12 + 13$

$perimeter = 30feet$

7 0

2 years ago